Answer:
The breadth of the triangle is 8 inches.
Step-by-step explanation:
Given that the area of the triangle is 24 sq inches and that the height is 6 inches
1/2 * b * 6 =24
b * 3= 24
b=8 inches
Answer: Rectangle, Rhombus, Square
Step-by-step explanation:
Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.
To find the rate of decent you would multiply the rate by time:
The equation is y = 32x
B. Replace x with 15 and solve for y:
Y = 32(15)
Y = 480
The rate of speed is 480 feet per second.
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
y = -3/5(x-3)
y= (-3/5) x + 9/5
Step-by-step explanation:
Step 1 :
The equation of line in point and slope form is (y- y intercept) = m(x-x intercept)
Where m represents the slope and x1 and y1 are points on the line.
Given (-2,3) and (3,0) are points on the line
m = (y2-y1)/(x2-x1) = (0-3)/(3-(-2)) = -3/5
So the equation of the line in point slope form is
(y-0)= -3/5(x-3) = y = -3/5(x-3) [taking the point as (3,0)]
Step 2 :
The equation of a line in slope and intercept form is y = m x +c
m denotes the slope and the constant c denotes the y intercept (the value of intercept in the y axis when x = 0)
when x = 0, y = 9/5 [using the equation in step 1]
Hence the equation in slope and intercept form is
y= (-3/5) x + 9/5
