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3 years ago

If you have a calendar that shows only the phases of the moon,can you predict when spring tides and neap tides will happen ?

1 answer:

6 0

Moon orbits earth. it's viewable somewhere in the world every 28 days. if the place where it's viewed were by the sea, then the tidal patterns of water - high tide and low tide - could be correlated to the moon being seen or otherwise. If the moon is is visible, it presumably gives one gravitational pull on the water. If the moon is not visible, then it presumably gives a less gravitational pull. Maybe "spring" suggests a high high tide (as in growth ?) and "neap" suggests a low high tide ???

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What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m

pychu [463]

Complete question:

A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?

Answer:

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

Explanation:

Velocity = Frequency X wavelength

V = Fλ ⇒ F = V/λ

F = 28/0.6 = 46.67 Hz

Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s

Average power supplied to the rope will be calculated as follows

$P_{avg} =\frac{1}{2} \mu \omega^2 A^2 V$

where;

ω is the angular frequency

A is the amplitude

V is the velocity

μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m

$P_{avg} =\frac{1}{2} ( 0.0348)(93.34 \pi )^2 (0.2)^2 (28)$ = 1676.159 watts

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

6 0

3 years ago

A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a

Verizon [17]

Answer:

The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus $S = 1\times10^{9}\ N/m^2$

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

$S=\dfrac{Fl_{0}}{A\Delta x}$

$\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}$

$\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}$

Put the value into the formula

$\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}$

$\Delta x=3.34\times10^{-6}\ m$

Hence, The shear deformation is $\Delta x=3.34\times10^{-6}\ m$ .

7 0

3 years ago

What distance will an object cover in 20 seconds if it is moving at 8 m/s

Nitella [24]

Answer:

160 m

Explanation:

distance covered in 1 s = 8 m

therefore, distance covered in 20 s = 8 * 20 m = 160 m

4 0

3 years ago

PLEASE HELP!! URGENTT!

oksano4ka [1.4K]

Answer:

120 Newton

Explanation:

Given the following data;

Mass = 12 kg

Angle = 4°

We know that acceleration due to gravity is equal to 10 m/s

To find the minimum force to stop the block from sliding;

Force = mgCos(d)

Where;

m is the mass of an object.

g is the acceleration due to gravity.

d is the angle of inclination (theta).

Substituting into the formula we have;

F = 12*10*Cos(4°)

F = 120 * 0.9976

F = 119.71 ≈ 120 Newton

3 0

3 years ago

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient o

NISA [10]

Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

pls give brainliest

3 0

3 years ago