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Ne4ueva [31]
2 years ago
14

Two uncharged, conducting spheres are separated by a distance d. When charge −Q is moved from sphere A to sphere B, the Coulomb

force between them has magnitude F0.
(a)Is the Coulomb force attractive or repulsive?



attractive repulsive



(b) If an additional charge −Q is moved from A to B, what is the ratio of the new Coulomb force to the original Coulomb force,(c) If sphere B is neutralized so it has no net charge, what is the ratio of the new to the original Coulomb force,
Physics
1 answer:
rosijanka [135]2 years ago
3 0

Answer: a) the force will be repulsive

b) the ratio of the new force to the old force will be 2

c) O

Explanation:

a) since charge -Q is moved from A to B, this implies that sphere A is negatively charged. The two spheres are now negatively charged and will repel themselves.

b) initial force will be -q(-Q)/d2

Adding extra charge -Q will cause change on B to become -2Q

The new force will be - 2Q(-q)/d2

Dividing new force by old force will give 2

C) if B is neutralized, the net charge becomes 0 and there will be no force on it.

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<span>Back in the day, one measured a printer's speed in CPM, which stands for characters per minute. Most of the modern printers that exist today, including the inkjet printer measure their speed in PPM, which is also known as pages per minute.</span>
5 0
3 years ago
You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3
jeka57 [31]

Answer:

W = 0J

Explanation:

The work done by the dresser is described as

W = f d (cos θ)

F has been given as the weight of this dresser. And it is 3500 N

d = 0 m

When you put these values into the equation

W = 3500 x 0 x cosθ

W = 0 J

This value tells us that the work done on this dresser is zero. No work has been done. Therefore the last option answers the question.

3 0
3 years ago
While vacationing in the mountains you do some hiking. In the morning, your displacement is S⃗ morning= (2200 m , east) + (4000
Minchanka [31]

Answer:

a

    The hiker (you ) is  200 m below his/her(your) starting point

b

   The resultant displacement in the north east direction is

a  = 6562.0 \  m

    The resultant displacement in vertical direction (i.e the altitude change )

  b =6503.1 \  m

Explanation:

From the question we are told that  

  The displacement in the morning is  S_{morning} =  (2200 \m , east) + (4000\ m\ north) + (100 \ m ,\ vertical)

   The displacement in the afternoon is  S _{afternoon}= (1300\ m ,\ west) + (2500 \ m ,\ north) - (300\ m ,\ vertical)

Generally the direction west is negative , the direction east is positive

                 the direction south is negative , the direction north is  positive

resultant displacement  is mathematically evaluated as  

    (2200 \m , east) +( - 1300\ m ,\ west) = 900 \ m \ east

     (4000\ m\ north)  + (2500 \ m ,\ north) = 6500  \ m ,\ north

     (100 \ m ,\ vertical) - (300\ m ,\ vertical) = -200 \ m

From the above calculation we see that at the end of the hiking the hiker (you) is  200 m below his/her(your) initial position

Generally from Pythagoras theorem , the resultant displacement in the north east direction is

      a  =  \sqrt{900^2 + 6500^2}

=>     a  = 6562.0 \  m

Generally from Pythagoras theorem , the resultant displacement in vertical direction (i.e the altitude change )

      b = \sqrt{6500^2 +(-200)^2  }

=>   b =6503.1 \  m

   

5 0
3 years ago
The
guapka [62]
The NUCLEUS is the center of the atom. it contains protons and NEUTRONS

protons have a POSITIVE charge

neutrons have a NEUTRAL charge

electrons have a NEGATIVE charge
6 0
3 years ago
Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high
Mashcka [7]

Answer:

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Explanation:

As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.

sin 50 = \frac{OM}{OP}

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meter

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

5 0
3 years ago
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