All categories

3 years ago

How many millimeters are in 251 cm?

Chemistry

2 answers:

Serga [27]3 years ago

4 0

Answer:

2510 mm

Explanation:

1 cm = 10 mm

251 cm = 10mm×251 = 2510 mm

antoniya [11.8K]3 years ago

3 0

Answer:

2510

Explanation:

Since there are 10 milimetres in 1 centimetre, 1 cm = 10mm

There are 10 times as many milimetres as centimetres.

251cm X 10 = mm

251cm = 2510mm

You might be interested in

what pressure must be applied to compress a gas from 85 L at 3.5 atm to 15 L? a-17.3atm b-24.7atm c-19.8atm d-21.4atm

pychu [463]

A... I think ., not sure

5 0

3 years ago

Imagine that Zapata was able to fly his machine far out into outer space. What do you predict would happen to Zapatas forward mo

scoray [572]

Answer:

B if they run out of fuel then they would probably keep going because there is nothing that would stop them other than like a planet or something.

Explanation:

5 0

3 years ago

Please help which one is it

creativ13 [48]

Answer:

d:more dense and falls

Explanation:

warm air Rises around cold air bc of its lower density. and when you have a lower density fluid or sum the lower density fluid rises and the higher density falls

6 0

3 years ago

Read 2 more answers

A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?

Nastasia [14]

Answer:

At -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where $P_{1}$ and $P_{2}$ are initial and final pressure respectively.

$V_{1}$ and $V_{2}$ are initial and final volume respectively.

$T_{1}$ and $T_{2}$ are initial and final temperature in kelvin scale respectively.

Here $P_{1}=150.0kPa$ , $V_{1}=1.75L$ , $T_{1}=(273-23)K=250K$ , $P_{2}=210.0kPa$ and $V_{2}=1.30L$

Hence $T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}$

$\Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}$

$\Rightarrow T_{2}=260K$

$\Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}$

So at -13 $^{0}\textrm{C}$ , the gas would occupy 1.30L at 210.0 kPa.

5 0

3 years ago

A plasma membrane and a cell wall _____.

klemol [59]

<h3>Answer;</h3>

D. Have different structures and different functions

A plasma membrane and a cell wall have different structures and different functions.

<h3>Explanation;</h3>

Plasma membrane is a structure that is found in both animal cell and plants cells. It is made up of a bi-layer consisting of lipid and proteins. Plasma membrane are semi-permeable which means the allow selective movement of materials in and out of the cell.

Cell wall, on the other hand is a structure that is found on plant cells and lacks in animal cell. It contains cellulose in its structure which enables it to be rigid and enhances it protect the cell from mechanical damage from harsh conditions such as pressure in the outside environment.

5 0

3 years ago

Read 2 more answers