Given what we know about Herbig-Haro (HH) objects, we can confirm that they are born from the collision between a jet from a star and clouds of interstellar matter.
<h3>What are Herbig-Haro (HH) objects?</h3>
- To put it simply, a Herbig-Haro (HH) object is what we observe as a bright spot in distant space. Upon closer observation we can observe that these giant bright patches are not lone objects, but in fact immense groups of interstellar matter.
<h3>How Herbig-Haro (HH) objects are formed.</h3>
- The formation of one of these interstellar groups requires an <em><u>immense amount of energy</u></em>. This energy come from the speed at which the materials that form these objects collide.
- As stated in the question, the jet released from a star in the process of being born <em><u>smashes into a giant cloud of </u></em><em><u>dust </u></em><em><u>and </u></em><em><u>interstellar material </u></em><em><u>to form the </u></em><em><u>Herbig</u></em><em><u>-</u></em><em><u>Haro </u></em><em><u>(HH) </u></em><em><u>objects</u></em>.
- This collision happens at hundreds of km/s. To put it into perspective, it would be roughly 500,000 miles per hour.
Therefore, we can confirm that option b, which states, "<em>where a jet from a </em><em>star </em><em>in the process of being born </em><em>collides </em><em>with (and lights up) a nearby cloud of </em><em>interstellar matter</em>", is the correct choice for the question pertaining to Herbig-Haro (HH) objects.
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brainly.com/question/7106246
Answer:
First option
Explanation:
Students 1 and 2 have precise measures yet is is not accurate since they measure around 5.
Answer: You Would have to .
Explanation:
Answer:
a, and f.
Explanation:
To be deprotonated, the conjugate acid of the base must be weaker than the acid that will react, because the reactions favor the formation of the weakest acid. The pKa value measures the strength of the acid. As higher is the pKa value, as weak is the acid. So, let's identify the conjugate acid and their pKas:
a. NaNH2 will dissociate, and NH2 will gain the proton and forms NH3 as conjugate acid. pKa = 38.0, so it happens.
b. NaOH will dissociate, and OH will gain the proton and forms H2O as conjugate acid. pKa = 14.0, so it doesn't happen.
c. NaC≡N will dissociate, and CN will gain a proton and forms HCN as conjugate acid. pKa = 9.40, so it doesn't happen.
d. NaCH2(CO)N(CH3)2 will dissociate and forms CH3(CO)N(CH3)2 as conjugate acid. pKa = -0.19, so it doesn't happen.
e. H2O must gain one proton and forms H3O+. pKa = -1.7, so it doesn't happen.
f. CH3CH2Li will dissociate, and the acid will be CH3CH3. pKa = 50, so it happens.