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PtichkaEL [24]
2 years ago
10

Four students all do the same experiment for the science fair. They test reaction times for pushing a button when a specific col

or is shown. Their data is as follows: ⎡⎣⎢⎢⎢⎢⎢⎢⎢⎢⎢⎢Student 1Student 2Student 3Student 4Reaction Time (seconds)Trial 10.440.350.410.42Trial 20.410.430.520.43Trial 30.470.380.570.41Trial 40.390.390.460.42Trial 50.460.420.550.41Trial 60.420.440.490.42⎤⎦⎥⎥⎥⎥⎥⎥⎥⎥⎥⎥ Put the students in order from most to least reliable data. A. Student 3, Student 2, Student 1, Student 4 B. Student 2, Student 1, Student 4, Student 3 C. Student 4, Student 1, Student 2, Student 3 D. Student 1, Student 2, Student 3, Student 4
Chemistry
1 answer:
dsp732 years ago
7 0

The order of the students from the most reliable to the least reliable is C. Student 4, Student 1, Student 2, Student 3.

<h3>what student has the most reliable data?</h3><h3 />

the student with the most reliable data is the one that has the least variation in their data in the various trials.

this student is therefore student 4.

the next student would be student 1 and student 2 would be the third most reliable.

student 3 has large variations in their trials which makes their data the least reliable.

find out more on reliable data at brainly.com/question/8391667.

#SPJ1

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3 years ago
Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a s
disa [49]

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

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[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid.  HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R   HSO_4^-    ⇄  H^+ + SO_4^2^-

I    0.14

C   - x               +x       +x

E   0.14-x        x         x

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K_a is large. It is no longer valid to approximate that [HSO^-_4] at equilibrium is the same as its initial value.

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x^2+1.3*10^-^2x - 0.14 × 1.3 × 10^-^2= 0

Solving the quadratic equation for x , x \geq 0 since x represents a concentration;

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Then, round the results to 2 significant figure;

  • [SO_4^2^-] = x = 0.037 mol. L ^-^1
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  • [HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1

Learn more about concentration here:

brainly.com/question/14469428

#SPJ4

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