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nadezda [96]
3 years ago
14

How has the scientific community addressed the safety of chemicals?

Chemistry
1 answer:
Sloan [31]3 years ago
6 0

Answer:

How has the scientific community addressed the safety of chemicals? ... Existing chemicals are tested if they have never been tested. before

Explanation:

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A stock solution has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L. What was the volu
erastova [34]

The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

<h3>How to calculate volume?</h3>

The concentration of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

  • C1 = initial concentration = 1.5M
  • C2 = final concentration = 0.54M
  • V1 = initial volume = ?
  • V2 = final volume = 0.18L

1.5 × V1 = 0.54 × 0.18

1.5V1 = 0.0972

V1 = 0.0972 ÷ 1.5

V1 = 0.065L

Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.

Learn more about volume at: brainly.com/question/1578538

3 0
2 years ago
When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of
baherus [9]
When dT = Kf * molality * i
                = Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
                               = 2.5g /250g x 1 mol /85 g x1000g/kg
                               =0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution 
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and  i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
     = (0.1176 * 0.359)^2 / (1-0.359)
     = 2.8x10^-3



5 0
3 years ago
Ii) During burning, elements in the coal are<br> converted to compounds called ????
elena-s [515]

Answer:

Gasification refers to the conversion of coal to a mixture of gases, including carbon monoxide, hydrogen, methane, and other hydrocarbons, depending on the conditions involved.

6 0
3 years ago
The volume of a sample of a gas at 273 c is 200.0 l. if the volume is decreased to 100.0 l at constant pressure, what will be th
Lyrx [107]
It will also be halved... but the relationship is with Kelvin not c.  So 273 +273 = 546 K.  half of that is 273 K, then subtract 273... you get 0 degrees c
7 0
4 years ago
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
3 years ago
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