Remove all perfect squares from inside the square root. \sqrt{63}= 63
1 answer:
3 is the answer obtained when the perfect squares are removed from
<u>Step-by-step explanation:</u>
is written as the
.
- Thus the 9 is the perfect square of 3 so by taking 9 out of the square root it becomes 3
- Thus the answer is 3
- Perfect square is said to be the number which is obtained by the twice the product of the every number.
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Answer:
X= -1/3
Step-by-step explanation:
In the picture it shows the work that i did
Given:
The equation of the circle is:
To find:
The radius of the circle.
Solution:
The standard form of a circle is:
...(i)
Where, (h,k) is the center and r is the radius.
We have,
In can be written as:
...(ii)
On comparing (i) and (ii), we get
Here, the center of the circle is the origin and the radius is equal to 4 units.
Therefore, the radius of the given circle is 4 units.