Question

Remove all perfect squares from inside the square root. \sqrt{63}= 63 ​

Answer 1

3$\sqrt{7}$ is the answer obtained when the perfect squares  are removed from $\sqrt{63}$

Step-by-step explanation:

• $\sqrt{63}$ is written as the $\sqrt{9*7}$.
• Thus the 9 is the perfect square of 3 so by taking 9 out of the square root it becomes 3
• Thus the answer is 3 $\sqrt{7}$
• Perfect square is said to be the number which is obtained by the twice the product of the every number.