If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:
The answer is B
Step-by-step explanation:
Because 3 1/5 as a decimal is 3.2
So 3.2 x 7 = 22.4
converted to a fraction is 11 2/5
and 22 2/5 simplified is 11 2/5
I’m not entirely sure but i think it might be s=lb^2 because the l, b, and b are all being multiplied together, and since you are multiplying and not adding the b’s, the two would go to b^2, and then you just multiply by l to get lb^2
Answer:

Step-by-step explanation:
First you have to find the slope
Now use the point-slope form by using one of the points and the slope. Let's use the point (3, 3)

Multiply thru the equation by 3 to remove the fraction
3y - 9 = -2(x - 3) =
3y - 9 = -2x +6
3y = -2x + 15
is the equation in slope-intercept form