Question

Is there a syntax error in the following code? bool hourlyWorker = true; if (hourlyWorker) cout << "The employee is an hourly worker.\n"; else cout << "The employee is not an hourly worker.\n";

Answer 1

Answer:

No, there is not

Explanation:

The code will print  -> The employee is an hourly worker.

Here is how:

- hourlyWorker is set as true

- Then we check this part of the code -> if (hourlyWorker)

- If this is true, then the code will print "The employee is an hourly worker."

- If not, then the code will print "The employee is not an hourly worker."

Since if (hourlyWorker) is true, it will print "The employee is an hourly worker."