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Nataly [62]
3 years ago
8

For each of the following acid-base reactions, calculate how many grams of each acid are necessary to completely react with and

neutralize 2.4 g of the base.HCl(aq)+NaOH(aq)→H2O(l)+NaCl(aq)
Chemistry
1 answer:
Anika [276]3 years ago
3 0

Answer:

m_{HCl}=2.19gHCl

Explanation:

Hello,

In this case, for the reaction between hydrochloric acid and sodium hydroxide, for 2.4 g of base, we can compute the neutralized grams of acid by applying the 1:1 molar ratio between them and their molar masses, 36.45 g/mol and 40 g/mol respectively as shown below by stoichiometry:

m_{HCl}=2.4gNaOH*\frac{1molNaOH}{40gNaOH}*\frac{1molHCl}{1molNaOH}*\frac{36.45gHCl}{1molHCl}\\   \\m_{HCl}=2.19gHCl

Best regards.

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What is the molarity of a solution prepared by dissolving 36. 0 g of naoh in enough water to make 1. 50 l of solution?
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0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.

Amount of NaOH = 36. 0 g

Amount of water = 1. 50 L

1 mol of NaOH = 40 g,

Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.9 / 1.50

Molarity of a solution = 0.6 mol / L

To  know more about Molarity refer to:  brainly.com/question/8732513

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