5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.
The answer should only have three significant figures, according to the numbers in the problem.
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The empirical formula of the metal oxide would be 
<h3>What is empirical formula?</h3>
Mass of scandium = 0.502g
Mass of scandium + oxygen = 0.768g
Mass of oxygen = 0.768 - 0.502 = 0.266g
Mole of scandium = 0.502/44.95 = 0.011
Mole of oxygen = 0.266/16 = 0.017
Divide by the lowest:
Scandium = 0.011/0.011 = 1
Oxygen = 0.017.0.011 = 1.5
Thus, the empirical formula of the compound would be
or 
More on empirical formula can be found here:brainly.com/question/14044066
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2 is the answer iam not sure about it
Yes
Answer: 336.2K
Explanation:
The boiling point is obtained from the standard enthalpy and entropy of vaporization as shown in the image attached.
Standard enthalpy of vaporization=35.3KJmol-1=35.3×10^3 Jmol-1
Standard entropy of vaporization= 105 JMol-1K-1
The formula and details of the solution are shown in the image attached.