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3 years ago

Explain in terms of stracture why metals are malleable?

1 answer:

3 0

I assume you mean 'structure' :)

Metals undergo metallic bonding. In this type of bond, metal atoms loose their valence electrons (that become delocalised). This type of bonding creates a regular layered lattice with positive metal ions and a sea of delocalised electrons floating between the layers. These layers slide over each other and results in metals being both malleable and ductile.

Hope it helps!

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Perform the following conversions:

jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=\frac{5}{9}\times (^oF-32)$

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=^oC+273$

(a) $1.06^oF$

$^oC=\frac{5}{9}\times (^oF-32)$

$^oC=\frac{5}{9}\times (1.06^oF-32)$

$^oC=-17.188$

The temperature in degree Celsius is, $-17.188^oC$

$K=^oC+273$

$K=-17.188+273$

$K=255.812$

The temperature in Kelvin is, 255.812 K

(b) $3410^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$3410^oC=\frac{5}{9}\times (^oF-32)$

$^oF=6106$

The temperature in degree Fahrenheit is, $6106^oF$

$K=^oC+273$

$K=3410+273$

$K=3683$

The temperature in Kelvin is, 3683 K

(c) $6.1\times 10^3K$

$K=^oC+273$

$6.1\times 10^3K=^oC+273$

$^oC=5827$

The temperature in degree Celsius is, $5827^oC$

$^oC=\frac{5}{9}\times (^oF-32)$

$5827^oC=\frac{5}{9}\times (^oF-32)$

$^oF=10456.6$

The temperature in degree Fahrenheit is, $10456.6^oF$

8 0

3 years ago

C2H6O(g) + 3O2(g) 2CO2(g) + 3H2O(g) Inside the piston of an automobile engine, 0.461 g of ethanol (C2H6O) gas reacts with 0.640

LuckyWell [14K]

Answer:

Oxygen is the limiting reactant.

Explanation:

Hello,

In this case, given the reaction:

$C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)$

Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:

$n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O$

Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:

$n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O$

In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.

Best regards.

5 0

3 years ago

Read 2 more answers

Continental waters are classified into two categories Lentic and Lotic. A Lotic Ecosystem has flowing waters, such as creeks,

Flauer [41]

Wind because it’s abiotic which means non living

8 0

3 years ago

Which of the following is an acid-base indicator? A) hydrochloric acid B)sodium hydroxide C)water D)phenolphthalein

KATRIN_1 [288]

D the answer is phenolphthalein