Answer:
i dont know how your teacher teaches it but in the first question take away the y after the 25. number 2 the start equation would be 55=2x+25 then you would subtract 25 from each side to get 30=2x, the divide by to to get x=15 or she made 15 calls. number 3 is correct.
i hope this helps
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
Learn more about TRIANGLE here brainly.com/question/2217700
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First you need to find the common denominator. Think of a number that both 2 and 5 can go in to evenly. 10 is the best number, so, make both denominators 10. What you do to the bottom, you must do to the top.
Now your equation is 5/10-2/10
Your answer is 3/10
Words over minutes.
So 36/(2/3)
Basically saying
36 * (3/2) = 54
<h3>
Answer: Choice C. (-1, -5)</h3>
Explanation:
The reflection rule we use is
when we want to reflect over the y axis. The x coordinate flips from positive to negative, or vice versa, while the y coordinate stays the same.
Therefore, 
