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N76 [4]
3 years ago
5

The rear wheel of a lawn tractor has a 20-inch radius. Find the angle (in radians) through which a wheel rotates in 23 seconds i

f the tractor is traveling at a speed of 13 miles per hour? Round to the nearest tenth if necessary.
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

263.12 radians

Step-by-step explanation:

The length of the rear wheel is given by:

L=2\pi r\\L=40\pi

The distance traveled by the lawn tractor in 23 seconds is:

d=13\frac{miles}{hour} *63360\frac{inch}{miles}*\frac{1\ hour}{3600\ seconds}*23\ seconds\\ d=5,262.4\ inches

The angle through which a wheel rotates is given by:

A=\frac{d}{L}*2\pi \\A=\frac{5,262.4}{40\pi}*2\pi\\A=263.12\ radians

The wheel rotates through a 263.12 radians angle.

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KatRina [158]

Answer: B

Step-by-step explanation:

The slope-intercept is usually written as y = mx + b form, where m is the slope, and b is the y-intercept. The y-intercept is the y value when x is equal to 0.

We can first eliminate C, because the y-intercept of the graph is 1.

To solve for slope, which is the m, choose two points, (-1, 5) and (1, -3).

Slope = (y2 - y1) / (x2 - x1)  

           = (-3 - 5) / (1 - (-1))

          = (-3 - 5) / (1 + 1)

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3 years ago
Very large or very small numbers are best input with exponential notation. For instance, the number 8,000,000 (eight million) is
Lerok [7]

Answer:

9*10^{12}km

Step-by-step explanation:

9,460,730,472,580.8 km

First, we can work out 5% of our number, by multiplying it by 0.05

9,460,730,472,580.8 * 0.05 = 473,036,523,629

Now, if we add and subtract our 5% calculated from our original number, we can work out the minimum and maximum value that our final answer can be in the range of.

9,460,730,472,580.8 + 473,036,523,629 = 9.933767*10^{12}\\9,460,730,472,580.8 - 473,036,523,629 =8.98769395*10^{12}

We can see that 9*10^{12} is in the range of valid answers, as:

8.9*10^{12} \leq 9*10^{12} \leq 9.9 * 10^{12}

So, our final answer is:

9*10^{12}km

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the answer is 0.75

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They are called "skew lines."

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