Try plugging in the equations
and d are not it because they eliminate x
4x-12=3x-4
x=8
4x-12=6x-18
2x=6
x=3
so both b and c work as answers
Answer:
The rate of change is 
or 1.75. That shows that the cost per video game is $1.75
Step-by-step explanation:
The change in y over change of x or slope can be calculated using the equation:
so take the last two points: (10, 25) and (15, 33.75).
33.75-25=8.75
15-10=5
8.75/5=<u>1.75</u><u> </u><u>(7/4)</u>
x=video games
y=total cost
Since slope is change in y (cost) per change of x (video games), the answer is:
1.75 cost per video game
Answer:
Option A. y = 4x
Step-by-step explanation:
From the question given above, the following data were obtained:
X >> Y
3 >> 12
4 >> 16
5 >> 20
6 >> 24
7 >> 28
Next, we shall use each of the options to obtain the first two value of y to which will correspond to the table above. This is illustrated below:
For Option A:
1. y = 4x
x = 3
y = 4 × 3
y = 12
2. y = 4x
x = 4
y = 4 × 4
y = 16
For Option B:
1. y = 4x + 12
x = 3
y = 4(3) + 12
y = 12 + 12
y = 24
2. y = 4x + 12
x = 4
y = 4(4) + 12
y = 16 + 12
y = 28
For Option C:
1. y = ¼ x
x = 3
y = ¼ × 3
y = ¾
2. y = ¼ x
x = 4
y = ¼ × 4
y = 1
For Option D:
1. y = ¼x + 12
x = 3
y = ¼(3) + 12
y = ¾ + 12
y = 51/4
2. y = ¼x + 12
x = 4
y = ¼(4) + 12
y = 1 + 12
y = 13
From the calculations made above, only option A ie. y = 4x correspond to the data given in the table above.
According to the formula...
P= 48/ 2x6
P=48/12
p=4
<span>60
Sorry, but the value of 150 you entered is incorrect. So let's find the correct value.
The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So
(300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500
So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that:
(375+x)(240+x)-90000 = 40500
The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation:
(375+x)(240+x)-90000 = 40500
x^2 + 375x + 240x + 90000 - 90000 = 40500
x^2 + 615x = 40500
x^2 + 615x - 40500 = 0
Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
