Answer:
n order to find the velocity of the moving object, you will need to divide the change in position by the change in time. Specify the direction moved, and you have the average velocity
I think 5.50 M x 35.0 mL x molar mass of RbOH = mass (g)
Answer:
As a gas is compressed in a cylinder its pressure
As the compression proceeds the volume of the chamber is decreasing and since mass is same, density increases. Similarly as volume decreases the number of gas molecules colliding with the walls increases as the density increases, so the pressure on the wall also increases.
The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
<h3>What is the mass in kg of the water on the roof after the rainstorm? </h3>
Generally, the equation for the Area of the roof is mathematically given as

height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density

In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
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