What is the net ionic equation for this reaction? FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl

2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh

Rufina [12.5K]

The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.

8 0

3 years ago

Read 2 more answers

2. A student mixes the above indicator with a sample of battery acid, an extremely strong acid. What

Nesterboy [21]

should be clear acid if im not mistaken

3 0

3 years ago

Butane gas (C4H10) burns in oxygen gas to produce carbon dioxide gas and water vapor. Balance the equation for this reaction (in

bixtya [17]

Answer:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

Explanation:

Butane gas (C₄H₁₀) burns in oxygen gas to produce carbon dioxide gas and water vapor. The unbalanced equation is:

C₄H₁₀(g) + O₂(g) ⇒ CO₂(g) + H₂O(g)

First, we will balance carbon and hydrogen which are in just one compound on each side.

C₄H₁₀(g) + O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

Finally, we will balance the oxygen atoms.

C₄H₁₀(g) + 6.5 O₂(g) ⇒ 4 CO₂(g) + 5 H₂O(g)

In order to have integers, we will multiply everý compound by 2.

2 C₄H₁₀(g) + 13 O₂(g) ⇒ 8 CO₂(g) + 10 H₂O(g)

5 0

3 years ago

Please help! you’ll be marked brainliest

Trava [24]

Answer:

Number of Protons:

Co: 27

Cl: 17

K: 19

S: 16

Al: 13

P: 15

Number of Electrons:

Co: 25

Cl: 18

K: 18

S: 18

Al: 10

P: 18

4 0

3 years ago

[H3O+] [OH−] pH Acidic or Basic 3.5×10−3 _____ _____ _____ _____ 3.8×10−7 _____ _____ 1.8×10−9 _____ _____ _____ _____ _____ 7.1

ankoles [38]

Answer:

See explanation below

Explanation:

I'm assuming this is a table you need to complete, so, you are not putting this in order, but I already found it in another place. let's do a little summary of the expressions we need to use in order to complete the chart.

To calculate pH we need the following expression:

pH = -log[H3O+] (1)

From this expression we can solve for [H3O+] in case we need it:

[H3O+] = 10^(-pH) (2)

When we have [OH-] we calculate the pOH and from there, the pH:

pOH = -log[OH-] (3)

and [OH-]:

[OH-] = 10^(-pOH) (4)

Finally to get the pH from pOH:

14 = pH + pOH

pH = 14 - pOH (5)

With these 5 expressions we can complete the chart. In picture 1, you have the actual chart.

To know if it's acidic or basic, that depends on the value of pH.

If pH <7 it's acidic

If pH >7 it's basic

If pH = 7 it's neutral

First case:

[H3O+] = 3.5x10^-3

pH = -log(3.5x10^-3) = 2.46 (acidic)

pOH = 14 - 2.46 = 11.54

[OH-] = 10^(-11.54) = 2.88x10^-12 M

Second case:

pOH = -log(3.8x10^-7) = 6.42

pH = 14 - 6.42 = 7.58 (it's basic)

[H3O+] = 10^(-7.58) = 2.63x10^-8 M

Third case:

pH = -log(1.8x10^-9) = 8.74 (it's basic)

pOH = 14 - 8.74 = 5.26

[OH-] = 10^(-5.26) = 5.5x10^-6 M

Fourth case:

[H3O+] = 10^(-7.15) =7.08x10^-8 M (Basic)

pOH = 14 - 7.15 = 6.85

[OH-] = 10^(-6.85) = 1.41x10^-7 M

Hope this can help you

7 0

3 years ago