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3 years ago

How many dm³ of hydrogen,measured at s.t.p.,would be needed to reduce 47.7g of copper(II) oxide to copper?

Chemistry

1 answer:

GaryK [48]3 years ago

4 0

Answer:

Option D. 13.44

Explanation:

We'll begin by calculating the number of mole in 47.7g of copper(II) oxide, CuO.

This can be obtained as follow:

Mass of CuO = 47.7 g

Molar mass of CuO = 63.5 + 16 = 79.5 g/mol

Mole of CuO =.?

Mole = mass /Molar mass

Mole of CuO = 47.7/79.5

Mole of CuO = 0.6 mole

Next, we shall write the balanced equation for the reaction. This is given below:

CuO + H2 —> Cu + H2O

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2 to produce 1 mole of Cu and 1 mole of H2O.

Next, we shall determine the number of mole of H2 needed to react completely with 0.6 mole of CuO.

This can be obtained as follow:

From the balanced equation above,

1 mole of CuO reacted with 1 mole of H2.

Therefore, 0.6 mole of CuO will also react with 0.6 mole of H2.

Finally, we shall determine the volume occupied by 0.6 mole of H2 at STP.

This can be obtained as follow:

1 mole of H2 occupied 22.4 dm³ at STP.

Therefore, 0.6 mole of H2 will occupy = 0.6 × 22.4 = 13.44 dm³.

Therefore, 13.44 dm³ of H2 is needed for the reaction.

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3 years ago

A. How many moles of CO will react with 1.75 moles of Fe,O,?

ehidna [41]

Answer:

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Explanation:

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3 years ago

Citrate synthase catalyzes the reaction: ????x????????o????c???????????????????? + ????c????????y???? − ????o???? → c???????????

Nady [450]

The given question is incomplete. The complete question is as follows.

Citrate synthase catalyzes the reaction

Oxaloacetate + acetyl-CoA $\rightarrow$ citrate + HS-CoA

The standard free energy change for the reaction is -31.5 kJ*mol^-1

( a) Calculate the equilibrium constant for this reaction a 37degrees C

Explanation:

(a). It is known that , relation between change in free energy ( $\Delta G$ ) of a reaction and equilibrium constant (K) is as follows.

$\Delta G = -RT \times ln K$

where, T = temperature in Kelvin

The given data is as follows.

T = 310 K, $\Delta G = -31.5 kJ /mol = -31500 J/mol$ (as 1 kJ = 1000 J)

Now, putting the given values into the above formula as follows.

ln K = $\frac{-(\Delta G)}{RT}$

= $\frac{31500}{8.314 \times 310}$

ln K = 12.22

K = antilog (12.22)

= $2.1 \times 10^{5}$

Therefore, we can conclude that value of equilibrium constant for the given reaction is $2.1 \times 10^{5}$ .

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3 years ago

What valence electron number do they all have in common

katovenus [111]

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2 years ago

2L of hydrogen has an initial pressure of 750 mmHg, what is the final pressure in mmHg if the volume increases to 20 L with a co

Verdich [7]

Answer: The final pressure is 75 mm Hg.

Explanation:

According to Boyle's law, at constant temperature the pressure of a gas in inversely proportional to volume.

Since, it is given that the temperature is constant. Hence, formula used is as follows.

$P_{1}V_{1} = P_{2}V_{2}$

Substitute the values into above formula as follows.

$P_{1}V_{1} = P_{2}V_{2}\\750 mm Hg \times 2 L = P_{2} \times 20 L\\P_{2} = \frac{750 mm Hg \times 2 L}{20 L}\\= 75 mm Hg$

Thus, we can conclude that the final pressure is 75 mm Hg.

3 0

3 years ago