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3 years ago

As the volume of a 1 mole sample of gas increases, with the temperature remaining constant, the pressure exerted by the gas:

1 answer:

7 0

I believe the correct answer would be decreases. At constant temperature, the volume and pressure are inversely related that is when one value increases the other decreases or as one decreases the other increases. Hope this helps. Have a nice day.

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Which is the average kinetic energy of particles in an object?

Wittaler [7]

Answer:

A temperature

Explanation:

3 0

3 years ago

Molecular chlorine and molecular fluorine combine to form a gaseous product. Under the same conditions of temperature and pressu

uranmaximum [27]

Answer:

Cl F₃

Explanation:

1) Reactants:

The reactants are:

Molecular chlorine: this is a gas diatomic molecule, i.e. Cl₂ (g)

Molecular fluorine: this is also a gas diatomic molecule: F₂ (g)

2) Stoichiometric coefficients:

One volume of Cl₂ react with three volumes of F₂ means that the reaction is represented with coefficients 1 for Cl₂ and 3 for F₂. So, the reactant side of the chemical equation is:

Cl₂ (g) + 3F₂ (g) →

3) Product:

It is said that the reaction yields two volumes of a gaseous product; then, a mass balance indicates that the two volumes must contain 2 parts of Cl and 6 parts of F. So, one volume must contain 1 part of Cl and 3 parts of F. That is easy to see in the complete chemical equation:

Cl₂ (g) + 3F₂ (g) → 2Cl F₃ (g)

As you see, that last equation si balanced: 2 atoms of Cl and 6 atoms of F on each side, and you conclude that the formula of the product is ClF₃.

8 0

2 years ago

Balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl

Mumz [18]

Answer:

$K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)$

Explanation:

The products of this reaction are given by:

$K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)$

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

$Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)$

The following steps should be taken:

balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

$Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)$

balance oxygen atoms by adding 7 water molecules on the right:

$Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

balance the hydrogen atoms by adding 14 protons on the left:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

Similarly, tin(II) cation becomes tin(IV) cation:

$Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-$

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

$3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-$

Add them together:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)$

Adding the ions spectators:

$K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)$

7 0

3 years ago

Need help with this chemistry homework

Elza [17]

Answer:

10.0 ml and 35.0ml respectively

Explanation:

if A=10.0ml let B be x

Now,

Lets assume the pan is balanced

then,

x = 10.0 ml

Therefore B= 10.0 ml

[Repeat the same process in next question]

7 0

2 years ago

QUESTION 1

umka2103 [35]

B. Electricity
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5 0

2 years ago