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4 years ago

Y = -2x+ 7 has this type of slope A.positive B.negative C.Zero D.undefined

Mathematics

1 answer:

grigory [225]4 years ago

7 0

Answer:

B: Negative

Step-by-step explanation:

-2/1 is the slope which is negative.

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Find the average value fave of the function f on the given interval. f(t) = e^sin(t) cos(t), [0, π/2]

RideAnS [48]

The question is related to integration and we have to used the following formula

$\frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

$\frac{1}{\pi /2 -0}\int\limits^0_{\pi/2} {e^{sin t}cos t } \, dt$

$= \frac{2}{\pi}(e^{sin t})_{0}^{ \pi /2}$

$=\frac{2}{\pi}(e^{sin(\pi/2)} -e^{sin0})$

$=\frac{2}{\pi}(e -1)$

6 0

3 years ago

Add 4312base5 3444base5 qunary number please add qunary

Genrish500 [490]

9514 1404 393

Answer:

13311₅

Step-by-step explanation:

Each column gets the sum mod 5, with a carry to the next column of the quotient of the sum and 5. For example, in the units column, 2+4 = 11₅, so 1 is written in the units column as the sum, and 1 is carried to the 5s column (next one to the left).

Continuing in this fashion gives the sum 13311₅.

If you recognize that 3444₅ = 4000₅ -1, you can subtract 1 from 4312₅ and add 4 in the 5³ place (4th column from the right). That gives you ...

4311₅ +4000₅ = 13311₅

_____

The base-5 addition table is attached.

4 0

3 years ago

I don’t get it? Help

daser333 [38]

A - outliner
B- gap
C - cluster

A is an outliner point since it’s outside of the main area and away from the rest.

Meanwhile B is in between the main area, making B a gap point.

C is in the main area and is a cluster point

I might not be fully correct, but I hope I somewhat helped

5 0

3 years ago

Which fraction is not equivalent to 9/12<br> 15/20<br> 24/32<br> 6/8<br> 16/24

s2008m [1.1K]

Answer:

16/24

Step-by-step explanation:

9/12–> simplify to 3/4

3/4=15/20

24/32=3/4

6/8=3/4

16/24 is not equal

6 0

3 years ago

Read 2 more answers

Write an equation in standard form of the line passing through points

Aneli [31]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -\frac{4}{9} &,& \frac{4}{9}~) 
% (c,d)
&&(~ \frac{6}{5} &,& \frac{4}{5}~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{\frac{4}{5}-\frac{4}{9}}{\frac{6}{5}-\left( -\frac{4}{9} \right)}\implies \cfrac{\frac{4}{5}-\frac{4}{9}}{\frac{6}{5}+\frac{4}{9}}$

$\bf \cfrac{\quad \frac{36-20}{45}\quad }{\frac{54+20}{45}}\implies \cfrac{\quad\frac{16}{45} \quad }{\frac{74}{45}}\implies \cfrac{16}{45}\cdot \cfrac{45}{74}\implies \cfrac{16}{74}\implies \cfrac{8}{37}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-\cfrac{4}{9}=\cfrac{8}{37}\left[ x -\left( -\cfrac{4}{9} \right)\right]$

$\bf y-\cfrac{4}{9}=\cfrac{8}{37}\left( x +\cfrac{4}{9} \right)\implies y-\cfrac{4}{9}=\cfrac{8}{37}x+\cfrac{32}{333}
\\\\\\
y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{4}{9}\implies y=\cfrac{8}{37}x+\cfrac{32}{333}+\cfrac{148}{333}\implies y=\cfrac{8}{37}x+\cfrac{180}{333}
\\\\\\
y=\cfrac{8}{37}x+\cfrac{20}{37}\implies \stackrel{standard~form}{-\cfrac{8}{37}x+y=\cfrac{20}{37}}$

7 0

4 years ago