For number 3 the answer is solid: pizza
liquid: smoothie
gas: air diffuser
Answer:
See below
Explanation:
There are 3600 seconds / hr
7.2 s / 3600 s/hr = .002 hr
Car traveled 1/10 mile in .002 hr
1/10 mi / .002 hr = 50 mi/hr
Answer:
Here are a few commonly used types of shooting in basketball.
- Jump Shot. A jump shot is most frequently used for a mid to long-range shots, including shooting beyond the arc. ...
- Hook Shot. A hook shot is when the shot is made while your body is not directly facing the basket. ...
- Bank Shot. ...
- Free Throw. ...
- Layup. ...
- Slam Dunk.
Answer:
If the same volume of air is inhaled and exhaled, the air we breathe out normally weighs more than the air we breathe in.
Since the output from the body normally exceeds the input, breathing leads to weight loss.
Explanation:
If equal volumes of gas is inhaled and exhaled, the exhaled gas is heavier.
The inhaled gas contains Oxygen and majorly Nitrogen.
The exhaled gas contains CO₂, H₂O and a very large fraction of the unused inhaled air that goes into the lungs.
So, basically, the body exchanges O₂ with CO₂ and H₂O (and some other unwanted gases in the body) in a composition that CO₂, the heavier gas of the ones mentioned here, is prominent.
So, because the mass leaving the body is more than the mass entering, breathing leads to a loss of weight. This is one of the reasons why we need food for sustenance. Breathing alone will wear one out.
(a) 907.5 N/m
The force applied to the spring is equal to the weight of the object suspended on it, so:
The spring obeys Hook's law:
where k is the spring constant and 
is the stretching of the spring. Since we know 
, we can re-arrange the equation to find the spring constant:
(b) 1.45 cm
In this second case, the force applied to the spring will be different, since the weight of the new object is different:
So, by applying Hook's law again, we can find the new stretching of the spring (using the value of the spring constant that we found in the previous part):
(c) 3.5 J
The amount of work that must be done to stretch the string by a distance is equal to the elastic potential energy stored by the spring, given by:
Substituting k=907.5 N/m and 
, we find the amount of work that must be done:
