How are the magnetic field lines near the south pole of a magnet affected when a second south pole is brought near it?
2 answers:
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The work done by the machine is equal to the product between the force applied and the distance over which the force is applieds, so in this case:
And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
And the power of the machine is equal to the ratio between the work done by the machine and the time taken:
consider the motion along the X-direction
X = horizontal displacement = 80 m
= initial velocity along the x-direction = v Cos60
t = time of travel
using the equation
X = t
80 = (v Cos60) (t)
t = 160/v eq-1
consider the motion in vertical direction :
Y = vertical displacement = 20 m
= initial velocity in Y-direction = v Sin60
a = acceleration = - 9.8 m/s²
t = time of travel = 160/v
using the equation
Y = t + (0.5) a t²
20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²
v = 32.5 m/s