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3 years ago

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PLS ANSWER What is the difference between direct and alternating current? (Be sure to write in complete sentences starting with

a capital and ending with a period.)

1 answer:

IgorC [24]3 years ago

7 0

Direct current (DC) is the flow of electric charge in only one direction. ... Alternating current (AC) is the flow of electric charge that periodically reverses direction. If the source varies periodically, particularly sinusoidally, the circuit is known as an alternating current circuit.

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Show that the expression pRT has the same units as the pressure, and thus that the ideal gas law is dimensionally consistent.

Gemiola [76]

Answer and Explanation:

We have given the expression $\rho RT$

Dimension of $\rho =ML^{-3}$

Dimension of R which is gas constant $=ML^2T^{-2}\Theta ^{-1}M^{-1}$

Dimension of temperature T $\Theta ^{-1}$

And dimension of pressure $ML^{-1}T^{-2}$

Now combine dimension of $\rho RT$ $=ML^{-3}ML^2T^{-2}\Theta ^{-1}M^{-1}\Theta ^{-1}=ML^{-1}T^{-2}$

So the dimension of $\rho RT$ and dimension P is same so there unit will also be same

From ideal gas equation we know that $PV=nRT$

$P=\frac{n}{V}RT=\rho RT$

As the both P and $\rho RT$ has same dimension so they are dimensionally constant

7 0

4 years ago

A car slows down at -5.00 m/s² until it comes to a stop after travelling 15.0 m. What was the initial speed of the car?

lapo4ka [179]

<h2>Answer: 12.24m/s</h2>

According to <u>kinematics</u> this situation is described as a uniformly accelerated rectilinear motion. This means the acceleration while the car is in motion is constant.

Now, among the equations related to this type of motion we have the following that relates the velocity with the acceleration and the distance traveled:

$V_{f}^{2}-V_{o}^{2}=2.a.d$ (1)

Where:

$V_{f}$ is the Final Velocity of the car. We are told "the car comes to a stop after travelling", this means it is 0.

$V_{o}$ is the Initial Velocity, the value we want to find

$a$ is the constant acceleration of the car (the negative sign means the car is decelerating)

$d$ is the distance traveled by the car

Now, let's substitute the known values in equation (1) and find $V_{o}$ :

$0-V_{o}^{2}=2(-5m/{s}^{2})(15m)$ (2)

$-V_{o}^{2}=-150{m}^{2}/{s}^{2}$ (3)

Multiplying by -1 on both sides of the equation:

$V_{o}^{2}=150{m}^{2}/{s}^{2}$ (4)

$V_{o}=\sqrt{150{m}^{2}/{s}^{2}}$ (5)

Finally:

$V_{o}=12.24m/s$ >>>This is the Initial velocity of the car

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3 years ago

Can anyone heelp me plzz plzz

Natali5045456 [20]

I think the answer is c) 1
Hope it helps and have a good day

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3 years ago

What does the path of an object look like when it is in uniform motion?

marysya [2.9K]

Answer:

The path of an object in uniform motion is a straight line.

4 0

2 years ago

Read 2 more answers

A projectile is fired upward at an angle θ above the horizontal with an initial speed v0. At its maximum height, what are its ve

aliya0001 [1]

Answer:

$\vec{v}_{\rm max} = v\cos(\theta)(\^x)\\|\vec{v}_{\rm max}| = v\cos(\theta)\\\vec{a} = \vec{g} = -9.8\^y$

Explanation:

The equations of kinematics will be used to solve this question:

$y - y_0 = v_{y_0}t + \frac{1}{2}a_yt^2\\v_y^2 = v_{y_0}^2 + 2a_y(y - y_0)\\v_y = v_{y_0} + a_yt$

At its maximum height, the projectile has zero velocity in the y-direction. But its velocity in the x-direction is unaffected.

First, let's apply the above equations to the x-direction.

There is no acceleration in the x-direction. So, its velocity in the x-direction is constant during the motion.

$v_x = v_{x_0} + a_xt = v_{x_0} + 0\\v_x = v_{x_0} = v\cos(\theta)$

Therefore, the velocity vector of the projectile is

$v_{max} = v_x = v\cos(\theta)$

The speed of the projectile is the same.

The acceleration vector is constant during the motion and equal to the gravitational acceleration, which is -9.8 downwards.

7 0

4 years ago