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vampirchik [111]
3 years ago
7

How many centimeters are there in 1 foot? There are 12 inches in 1 foot. the ratio of centimeters to inches by the number of inc

hes in 1 foot to find how many centimeters are in 1 foot. There are centimeters in 1 foot.
Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer:

There are 0.0328 centimeters in 1 foot.

Step-by-step explanation:

Given : There are 12 inches in 1 foot.

To find : How many centimeters are there in 1 foot?

Solution :

1 foot = 12 inches

and 1 inch = 2.54 centimeter

So, 12 inches = 12\times 2.54 centimeter

12 inches = 30.48 centimeter

i.e. 1 foot = 30.48 centimeter

Then, 1 centimeter = \frac{1}{30.48} foot

1 centimeter = 0.0328 foot

Therefore, there are 0.0328 centimeters in 1 foot.

DaniilM [7]3 years ago
6 0

Answer:

30.48 centimeters

Step-by-step explanation:

In 1 foot there are 30.48 centimeters

In 1 inches there are 2.54 centimeters

There are 12 inches in foot

In one inch there are  foot

in 2.54 centimeters there are \frac{1}{12} foot

In 1 centimeter there are  \frac{1}{12}×\frac{1}{2.54} feet

In 1 centimeter there are \frac{1}{30.48} foot

Hence in 1 foot we get 30.48 centimeters

Hence, we get our answer

Hence, the correct answer is 30.48 centimeters

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Answer:

32 ft

Step-by-step explanation:

Given data

Length= 8ft

Area= 64 f^2

Let us find the width

Area= Length*Width

64= 8* Width

Width= 64/8

Width= 8ft

Hence the perimeter= 2L+2W

P= 2*8+2*8

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P= 32 ft

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X + 2y = 5 3x + 5y = 14 Solve the system of equations. (3, 1) (7, -1) (2, 3/2)
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Answer:

The solution is (3 , 1)

Step-by-step explanation:

To solve the system of the equation you can use the elimination method or substitution method.

We will use the substitution method

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In the second equation 3x + 5y = 14⇒we will substitute x by 5 - 2y

3(5 - 2y) + 5y =14

15 - 6y + 5y = 14

-6y + 5y = 14 - 15

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Substitute the value of y in x = 5 - 2y

x = 5 - 2(1) = 5 -2 =3

∴ The solution of the system of equations is (3 , 1)

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Given:

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Required:

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The graph of the sine function is as follows:

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