A random variable x is normally distributed with a mean of 100 and a variance of 25. Given that x = 110, its corresponding z- score is 0.40.
Answer: The given z-score is false.
Explanation: We are given:
Mean,
,
Variance, 



The z-score formula is given below:




Therefore, the z-score corresponding x=100 is 2
Therefore, the given z-score = 0.4 is false.
Answer:
The answer has many ongoing 3's so just shorten it to
8.3 or 8.33
Answer:
A) M = 3.016
B) M = 9.79
C) 62
Step-by-step explanation:
A) We are given;
Population size; n = 100
standard deviation; σ = 12
Formula for the margins of error is;
M = z × σ/√n
At 99% confidence interval, z = 2.58
Thus;
M = 2.58 × 12/√100
M = 3.016
B) n is now equal to 10, thus at same confidence interval used in option A, we have;
M = 2.58 × 12/√10
M = 9.79
C) to solve this, we will use the formula;
n ≥ (zσ/m)²
Where;
z at 95% confidence interval has a value of 1.96
m is the margin of error = 3
Thus;
n ≥ (1.96 × 12/3)²
n ≥ 61.4656
Thus,approximately n = 62