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sineoko [7]
3 years ago
10

#1 Using the right triangle below, find the cosine of angle A.

Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer: 0.8

Step-by-step explanation:

Using the Cosine formula :

Cos A = \frac{b^{2}+c^{2}-a^{2}}{2bc}

a = 6

b = 8

c = 10

substituting into the formula , we have

Cos A = \frac{8^{2}+10^{2}-6^{2}}{2(8)(10)}

Cos A = \frac{64+100-36}{160}

Cos A = \frac{164-36}{160}

Cos A = \frac{128}{160}

Therefore :

Cosine of angle A = 0.8

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If x + 3y = 11 and xy = 6, find the value of x²+9y
Galina-37 [17]

Answer:

x {}^{2}  +  {9y}^{2}  = 85

, it's 85

Step-by-step explanation:

for explanation see the attachment.

6 0
3 years ago
Hannah notices that segment HI and segment KL are congruent in the image below: Two triangles are shown, GHI and JKL. G is at ne
BlackZzzverrR [31]

Answer:

segment IG ≅ segment LJ

Step-by-step explanation:

Please refer to the attached image as per the triangles as given in the question statement.

\triangle HGI, \triangle JKL

G\left(-3,1\right),\ H\left(-1,1\right),\ I\left(-2,3\right)

J\left(3,3\right),K\left(1,3\right),L\left(2,1\right)

Given that:

HI\cong KL and

\angle I \cong \angle L

<em>SAS congruence </em>between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.

We are given that one angle and one sides are congruent in the given triangles.

We need to prove that other sides that makes this angle are also congruent.

To show the triangles are congruent i.e. \triangle GHI \cong \triangle JKL by SAS congruence we need to prove that

segment IG ≅ segment LJ

Let us use Distance formula  to find IG and LJ:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

IG  =\sqrt{(-2+3)^2+(3-1)^2} =\sqrt5\ units

LJ  =\sqrt{(2-3)^2+(1-3)^2} =\sqrt5\ units

Hence, segment IG ≅ segment LJ

\therefore ΔGHI ≅ ΔJKL by SAS

4 0
3 years ago
Please help me with my math problem!!Thank you!! :)
vova2212 [387]

Check the picture below.

6 0
4 years ago
The surface area of the above figure is?
scoray [572]

Answer:

The surface area is 125.66 cm^2

Hope this helps!

8 0
3 years ago
Work out the perimeter of this semicircle, take pie to be 3.142<br> radius= 10cm
deff fn [24]

Answer:

30 cm

Step-by-step explanation:

Perimeter = (half the circumference) + (twice the radius)

                 = (1/2)(2·10 cm)                   +  2(10 cm)

                 = 10 cm + 20 cm

                  = 30 cm

3 0
3 years ago
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