OK SO THE THING WE HAVE TO FACTOR DOESN"T RELATE TO THE PROBLEM
easy way to solve is factor -72 and find what factos add up so 34 -72= 1,-72=-71 no 2,-36=-34 correct therefor the numbers are 2 and -36 that was easy now the legit math way
so
xy=-72 x+y=-34
x+y=-34 subtract x y=-34-x subsitute x(-34-x)=-72 -34x-x^2=-72 add 34x+x^2 to bboth sides 0=x^2+34x-72 factor facotr -72 and find what 2 factors add up to 34 -2 and 36 add up to 34
(x-2)(x+36)=0 set each to zero x-2=0 add 2 x=2
x+36=0 subtract 36 x=-36
the numbers are 2 and -36
Second question factor 3x^2-34x-24 which has nothing to do with the problem except ahthat 3 times 24=72
we do is we factor the first term 3=1 times 3 we know that it will be in a form liike (somethingx+something)(somethingx+something) so we put the 1 and 3 for the first somethings (3x+ something)(1x+something) then we factor 24 24=1 and 24 or 2 and 12 or 3 and 8 or 4 and 6 let's pick a random pair 2 and 12 they have to be different signs since the last term is negative since midlde term is also negative, we know that bigge number is negative so (3x+2)(x-12) we expand 3x^2+2x-36x-24 3x^2-34x-24
ok, so I don't know what the equiqation was for but numbers are 2 and -36 facotre form of equation that didn't relate=(3x+2)(x-12)
