<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
-1058
Step-by-step explanation:
F-1:
y=x+9
y-9=x
x-9=f-1
f-1(14)=14-9=5 f-1(5)=5-9=-4 f-1(-5)=-5-9=-14 f-1(25)=25-9=16
f(14)=14+9=24 f(5)=5+9=14 f(-5)=9-5=4 f(25)=25+9=34
Answer:
2.21 i believe
Step-by-step explanation:
Answer:
The answer to 9 is table A
Step-by-step explanation:
The table has the value of x as -4 in two different spots, therefore it would fail the vertical line test. You could change one of the two values with -4 to anything but -4
