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3 years ago

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A 5.0 kg block hangs from a spring with spring constant 2000 N/m. The block is pulled down 5.0 cm from the equilibrium position

and given an initial velocity of 1.0 m/s back towards equilibrium. a) What is the total mechanical energy of the motion

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

Explanation:i think this would help u

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What happens when a person’s immune system is very weak?

Alexeev081 [22]

The correct answer is C) becuse without certain medicine they will dieeeee

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3 years ago

Positive feedback interactions in earth’s systems are always a result of human action. T/F

VLD [36.1K]

Positive feedback interactions in earth’s systems are always a result of human action is a FALSE statement.

<u>Explanation:</u>

Earth is a unstable equilibrium which tends to move out of equilibrium, but several other factors try to bring it back in equilibrium again. Earth has a different actions going on both on its surface and also inside it.

Human can alter, or can modify a very small part of the events that occur on earth’s surface. But they don’t have any control on what’s going inside earth’s core. So positive feedback interactions are not only the results of human interaction, but also different other factors.

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3 years ago

Alice and Tom dive from an overhang into the lake below. Tom simply drops straight down from the edge, but Alice takes a running

crimeas [40]

Answer:c

Explanation:

Given

Alice launches with horizontal velocity $u=25\ m/s$

Tom simply drops straight down from the edge

Time taken by both the person is same as they have same initial vertical velocity i.e. zero so the time taken to reach the ground is zero.

Although Alice will travel more horizontal distance compared to Tom.

Thus option c is correct

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3 years ago

If half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve o

Scilla [17]

Answer:

Maximum acceleration will be equal to $3.43m/sec^2$

Explanation:

We have given coefficient of kinetic friction $\mu _k=0.7$

And coefficient of static friction $\mu _s=1$

Acceleration due to gravity $g=9.8m/sec^2$

When truck moves maximum force will be equal to $F=\mu _kmg$

It is given that half of the weight is supported by its drive wheels

So force required $=\frac{\mu _kmg}{2}$

From newtons law maximum acceleration will be equal to $a=\frac{\frac{\mu _kmg}{2}}{m}=\frac{\mu _kg}{2}=\frac{0.7\times 9.8}{2}=3.43m/sec^2$

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3 years ago

A 142 kg boulder is located near the edge of a cliff 25 m above the ground. What is the gravitational potential energy of the bo

jarptica [38.1K]

PE = mass * height * 9.81
PE = 142 * 25 * 9.81
PE = 34825.5 J

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3 years ago

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