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mestny [16]
3 years ago
11

A current of 1.8 A delivers 2.5 C of charge.

Physics
2 answers:
Verdich [7]3 years ago
7 0

Answer:

<em>1.4 seconds</em><em>,</em><em> </em>which is the third option

Explanation:

Current is defined as the flow of charge per time

Therefore, the equation that relates current, charge and time can be expressed as follows:

I = ΔQ / ΔT

where:

I is the current given = 1.8 ampere

ΔQ is the charge given = 2.5 coulomb

Δt is the time required for the flow of the given charges to give the 1.8 ampere.

Substitute with the givens in the above equation to get the time as follows:

1.8 = 2.5 / ΔT

ΔT = 2.5 / 1.8 = 1.38888 which is approximately 1.4 seconds

I am Lyosha [343]3 years ago
4 0

" 1.8 Ampere " means "1.8 Coulomb/sec".

(2.5 C)/(1.8 C/sec) = (2.5/1.8) (s) = <em>1.39 sec </em>

I honestly don't see where any of the choices comes from, but the closest one is (C) 1.45 sec.

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Which properties of a lava lamp are important to remember when modeling convection?
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The atoms in a sidewalk on a hot summer day are vibrating _____ the atoms in the sidewalk on a freezing day in winter.
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Answer:

(A) more rapidly than

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With higher temperatures, object's molecules (and atoms) have higher kinetic energy which is due to faster "jiggling" (vibrations). On a hot day these vibrations in the material the sidewalk is made of are more rapid than on a cold day, just as their temperatures differ.

7 0
3 years ago
Read 2 more answers
In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53×10−10m
Ksenya-84 [330]

Answer

given,

radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m

mass of electron, M = 9.11 x 10⁻³¹ Kg

charge of electron, q₁ = 1.6 x 10⁻¹⁹ C

                                q₂ = 1.6 x 10⁻¹⁹ C

we know, force between two charges

F = \dfrac{kq_1q_2}{r^2}

F = \dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.53\times 10^{-10})^2}

  F = 8.20 x 10⁻⁸ N

b) using newton's second law

F = m a

m a =  8.20 x 10⁻⁸

a =\dfrac{8.20\times 10^{-8}}{9.11\times 10^{-31}}

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c) speed of the electron

 a =\dfrac{v^2}{r}

 9\times 10^{22} =\dfrac{v^2}{0.53\times 10^{-10}}

   v² = 4.77 x 10¹²

  v = 2.18 x 10⁶ m/s

d) the period of the circular motion.

    T=\dfrac{2\pi}{\omega}

    T=\dfrac{2\pi r}{v}

    T=\dfrac{2\pi\times 0.53\times 10^{-10}}{2.18\times 10^6}

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8 0
3 years ago
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A ball is spun around in circular motion such that its frequency is 10 Hz.
Scilla [17]

Answer:

a = 0.1 s b. 10 s

Explanation:

Given that,

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(b) Frequency is number of rotations per unit time. So,

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Hence, this is the required solution.

5 0
2 years ago
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