Calculate the work done when a 10 N force pushes against a cart 4.0 m
2 answers:
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Answer:
r = 5.08 m
Explanation:
The electric force of attraction or repulsion is given by :
We need to find how far above the electron would the proton have to be if you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it.
So, the force from the proton is balanced by the mass of the electron.
r is distance
So, proton have to be at a distance of 5.08 meters above the electron.
Answer:
Heat Flow Rate : ( About ) 87 W
Explanation:
The heat flowing out of the system each minute, will be represented by the following equation,
Q( cup ) + Q( water ) = m( cup ) c( al )
ΔT + m( w )
c( w )
ΔT
So as you can see, the mass of the aluminum cup is 150 grams. For convenience, let us convert that into kilograms,
150 grams = .15 kilograms - respectively let us convert the mass of water to kilograms,
800 grams = .8 kilograms
Now remember that the specific heat of aluminum is 900 J / kg K, and the specific heat of water = 4186 J / kg
K. Therefore let us solve for " the heat flowing out of the system per minute, "
Q( cup ) + Q( water ) = .15 ( 900 J / kg
K )
1.5 + .8
( 4186 J / kg
K )
1.5,
Q( cup ) + Q( water ) = 5225.7 Joules
And the heat flow rate should be Joules per minute,
5225.7 Joules / 60 seconds = ( About ) 87 W