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3 years ago

What is the area of triangle ABC?

Mathematics

2 answers:

Ann [662]3 years ago

7 0

Answer:

A = 3 units^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the length of the base and h is the height

b = the distance from B to C = 4 units = 2 ( watch the scale)

h = the distance from A to C along the x axis =6 units = 3 (watch the scale)

A = 1/2 (2)(3)

A = 3 units^2

aliya0001 [1]3 years ago

4 0

Answer:

B 3 sq un

on edge

Step-by-step explanation:

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Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

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3 years ago

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Leviafan [203]

Answer:

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Step-by-step explanation:

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2 years ago

How many times can 8 into 12

Lisa [10]

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6 0

2 years ago

Read 2 more answers

Find the 5th term of the sequence in which T1=8 and Tn=3t n-1

yan [13]

T_n = 3 * T_(n-1)

Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1

T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!

Short way (sometimes it works!)

T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
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2 years ago

Use the figure below to find the value of x and PQ.

Scilla [17]

Answer:

x=14

PQ=46

Step-by-step explanation:

PT and TQ are equal, so we can set up the equation like this: PT=TQ

23=2x-5

calculate to find x

x=14

PQ is just PT+TQ so 23+23=46

7 0

2 years ago