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PIT_PIT [208]
3 years ago
7

Write 100,000+4,000+40+7 in standard notation

Mathematics
2 answers:
labwork [276]3 years ago
8 0
In standard notation it is 104,047
anyanavicka [17]3 years ago
3 0
Hi there!

The standard notation would be 104,047

Hope this helps ;)
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Which expression has a value that is equivalent to the given expression when n = 8?
mrs_skeptik [129]

Q1.

Put the value of n = 8 to the expressions:

2n + 10 → 2(8) + 10 = 16 + 10 = 26

A: 3n → 3(8) = 24 ≠ 26

B: 2(n + 5) → 2(8 + 5) = 2(13) = 26   :)

C: n² + 5 → 8² + 5 = 64 + 5 = 69 ≠ 26

D: 10n + 2 → 10(8) + 2 = 80 + 2 = 82 ≠ 26

<h3>Answer: B: 2(n + 5)</h3>

Q2.

x = 3, y = 2

L = 5y² - 2x → L = 5(2)² - 2(3) = 5(4) - 6 = 20 - 6 = 14

R = x² + ... → R = 3² + ... = 9 + ...

A: x² + x → 9 + 3 = 12  NOT

B: x² + y → 9 + 2 = 11   NOT

C: xy → 9 + (3)(2) = 9 + 6 = 15 YES

D: 2y → 9 + (2)(2) = 9 + 4 = 13   NOT

5y² - 2x < x² + xy

L = 14, R = 15, L < R    CORRECT

<h3>Answer: C: xy</h3>

Q3.

3 + 6² = 3 + 36 = 39

A: 3³ + 12 = 27 + 12 = 39  NOT

B: 5² + 4² = 25 + 16 = 41 > 39    YES

C: 2³ + 5² + 6 = 8 + 25 + 6 = 39    NOT

D: 2³ + 14 + 17 = 8 + 14 + 17 = 39    NOT

<h3>Answer: B: 3 + 6² < 5² + 4²</h3>
6 0
3 years ago
What is the greatest common factor you can use to divide the numerator and denominator of the fraction 28/32?
Anastaziya [24]
The greatest common factor is 4.

28/32 / 4 = 7/8
7 0
3 years ago
Write a math problem that includes multiplying decimals.Explain how you know where to place the decimal in the product.
disa [49]

Answer:

0.1 x 2 = 0.2

Step-by-step explanation:

when you multiply, you move the decimal once because there is one decimal place.

6 0
2 years ago
Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
The scatterplot below represents the amount of paper left in an office copy machine in the month of June.
monitta

Answer:

75

Step-by-step explanation:

5 0
3 years ago
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