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3 years ago

According to "Operating Your ACME W914 Camera," how can you permanently delete a picture from your camera?

Mathematics

2 answers:

Pie3 years ago

7 0

Answer:

I don't believe there is a way to permentley delete something unless it is on a camara, you could destroy the ip, but if on a mobile phone you can delete the picture but what have to wait for it to be oved off uld if

Step-by-step explanation:

Lapatulllka [165]3 years ago

6 0

Answer: by pressing the ERASE button.

Step-by-step explanation: Hope this helped :D

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Nathan and Steven stacked boxes on a shelf. Nathan lifted 13 boxes and Steven lifted 15 boxes. The boxes that Nathan lifted each

bearhunter [10]

Http://www.jiskha.com/display.cgi?id=1412206557 here this should help

4 0

3 years ago

Solve the triangle.

saw5 [17]

Answer:

Step-by-step explanation:

because c is shorter than a we know C is a smaller angle than A

so the first choice is out.

use the law of cosines to find b

$b^{2}$ = $a^{2} +c^{2} -2*a*c*cos(B)$

$b^{2}$ =1681+400-1326.787871

$b^{2}$ = 754.21219

b= $\sqrt{754.21219}$

b= 27.46292

so the last choice looks good

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3 years ago

Who got the Bad Bunny Crocs?

Lady_Fox [76]

Answer:

I doo

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Hans wanted to find the length of the hypotenuse of the triangle. Which statement correctly identifies his error?

KonstantinChe [14]

Choice 1. He did not square 40, he just multiplied by 2.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse measures c cm while the other sides are 40 cm and 9 cm each.

Step 2:

According to the Pythagorean theorem,

$9^{2} +40^{2} = c^{2}.$

$81 + 1600 = c^{2} .$

$1681 = c^{2} .$

$\sqrt{1681} = c.$

This is the correct solution to the given problem. Hans did not square 40, he just multiplied by 2. Which is the first option.

5 0

3 years ago

Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

Comment on Six Sigma

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago