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Svetach [21]
3 years ago
13

Objects of different mass were used to see whether the acceleration due to gravity depends on the mass of a falling object. In o

ther words, does a heavier object fall faster than a lighter object? What do the experimental results show?
Physics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

No, the two objects fall with the same acceleration

Explanation:

For an object in free fall, the only force acting on it is the force of gravity, acting downward, of magnitude

F=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law of motion, we can find the acceleration of the object by using

F=ma

where F is the net force on the object and a is the acceleration.

Equating the two equations, we get:

ma=mg\\a=g

Which means that the acceleration of any object in free fall is always g, regardless of its mass. Therefore, a heavier object and a ligher object falls with the same acceleration, and so with same velocity.

However, this is not what experimental results show. The reason is that an object in free fall on Earth is not under vacuum, but there is another force acting on it: the air resistance, acting upward and resisting the motion of the object. The magnitude of the air resistance depends on several factors, such as density of the medium, shape of the object, speed: as a result, a heavier object and a lighter object will fall at different rates, due to the presence of this force.

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A motorist is driving at 20m/s when she sees that a traffic light 200m ahead has just turned red. She knows that this light stay
yuradex [85]

Answer:

5.71428571422 m/s

Explanation:

u = Initial velocity = 20 m/s

v = Final velocity

s = Displacement

a = Acceleration

Time taken = 15-1 = 14 s

Distance traveled in 1 second = 20\times 1=20\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 200-20=20\times 14+\frac{1}{2}\times a\times 14^2\\\Rightarrow a=\frac{2(180-20\times14)}{14^2}\\\Rightarrow a=-1.02040816327\ m/s^2

v=u+at\\\Rightarrow v=20-1.02040816327\times 14\\\Rightarrow v=5.71428571422\ m/s

The speed as she reaches the light at the instant it turns green is 5.71428571422 m/s

4 0
3 years ago
Would the forces acting on the sky diver be balanced or unbalanced? Explain your answer.
docker41 [41]

Answer:

your mom is balanced!!!

4 0
3 years ago
An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (
nataly862011 [7]

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

6 0
3 years ago
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

5 0
3 years ago
5 sentences about the mouth​
AlladinOne [14]
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7 0
3 years ago
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