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3 years ago

13

Give reason The SI system of unit is better than the MKS system

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

The SI was and is intended to extend and refine the definitions used by the MKS.

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A charged particle isinjected into a uniform magnetic field such that its velocity vector is perpendicular to themagnetic field

Bumek [7]

Answer:

D) follows a circular path

Explanation:

This is because the magnetic force F on the charge, q due to the magnetic field B with velocity vector v perpendicular to it, equals the centripetal force acting on the charge.

So, F = Bqv = mv²/r.

So it follows a circular path.

4 0

4 years ago

Read 2 more answers

Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).

timofeeve [1]

Answer:

$\lambda=3.64\times 10^{-12}\ m$

Explanation:

We have,

Speed of an electron is $2\times 10^8\ m/s$

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

$\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m$

So, the De-Broglie wavelength of an electron is $3.64\times 10^{-12}\ m$

4 0

3 years ago

What is the momentum of an 18-kg object moving at 0.5 m/s?

Arada [10]

Answer:

9kgm per second

Explanation:

3 0

2 years ago

Read 2 more answers

In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin

GuDViN [60]

Answer:

The velocity is $v_b = 20.17 \ m/s$

Explanation:

From the question we are told that

The mass of the ball is $m = 0.245 \ kg$

The radius is $r = 59.8 \ cm = 0.598 \ m$

The force is $F = 30.9 \ N$

The speed of the ball is $v = 16.0 \ m/s.$

Generally the kinetic energy at the top of the circle is mathematically represented as

$K_t = \frac{1}{2} * m * v^2$

=> $K_t = \frac{1}{2} * 0.245 * 16.0 ^2$

=> $K_t = 31.36 \ J$

Generally the work done by the force applied on the ball from the top to the bottom is mathematically represented as

$W = F * d$

Here d is the length of a semi - circular arc which is mathematically represented as

$d = \pi * r$

So

$W = 30.9 * 0.598$

$W = 18.48 \ J$

Generally the kinetic energy at the bottom is mathematically represented as

$K_b = \frac{1}{2} * m * v_b^2$

=> $K_b = \frac{1}{2} * 0.245 * v_b^2$

=> $K_b = 0.1225 * v_b^2$

From the law of energy conservation

$K_t + W =K_b$

=> $31.36+ 18.48 = 0.1225 * v_b^2$

=> $v_b = 20.17 \ m/s$

3 0

3 years ago

A system is said to be in a state of dynamic equilibrium when the

ExtremeBDS [4]

forward reaction equals reverse reaction

3 0

3 years ago