C.
Newton’s Second Law is F=ma (force is equal to the mass multiplied by acceleration), however, the equation can be rearranged to isolate and calculate mass from force over acceleration. Therefore, m=F/a
Answer:
The new force is 1/4 of the previous force.
Explanation:
Given
---- 
--- 
Required
Determine the new force
Let the two particles be q1 and q2.
The initial force F1 is:
--- Coulomb's law
Substitute 2 for r1


The new force (F2) is

Substitute 4 for r2



Substitute 


The new force is 1/4 of the previous force.
Hi!
The main component of all computer memory is RAM.
Hope this helps !
Answer:

Explanation:
Given that,
Wavelength, 
We need to find the frequency of the violet light.
We know that the relation between frequency and wavelength is given by :

So, the frequency of violet light is
.