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Mashutka [201]
3 years ago
12

PLS HELP ASAP Given the following probabilities, for what P(B) are events A and B independent? P(A)=23 P(A and B)=13

Mathematics
1 answer:
Paul [167]3 years ago
8 0

I'm assuming you meant to say

P(A) = 2/3

P(A and B) = 1/3

If that is the case, then A and B are independent if and only if the following equation is true

P(A and B) = P(A)*P(B)

So we multiply P(A) and P(B) to get the value of P(A and B). We don't know what P(B) is, but we can use algebra to find it

-------------------------

P(A and B) = P(A)*P(B)

P(A)*P(B) = P(A and B)

(2/3)*P(B) = 1/3

P(B) = (1/3)*(3/2) .... multiply both sides by the reciprocal of 2/3

P(B) = (1*3)/(3*2)

<h3>P(B) = 1/2  is the answer</h3>

------------------------

If P(B) = 1/2, then

P(A and B) = P(A)*P(B)

P(A and B) = (2/3)*(1/2)

P(A and B) = (2*1)/(3*2)

P(A and B) = 1/3

Which is the given probability for both events happening. This confirms we have the correct P(B) value.

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The short leg of a 90-45-45 triangle is 3 and the long leg is 7. The hypotenuse would be c = \sqrt{58}.

<h3>What is the Pythagoras theorem?</h3>

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The short leg of a 90-45-45 triangle is 3 and the long leg is 7.

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