<span>Let us assume that the rate of decay follows a 1st
order reaction. Therefore the formula for rate of decay is:</span>
<span>A = Ao e^-kt --->
1</span>
Where,
A = final value after time t
Ao = initial value at t zero
k = rate constant
t = time elapsed
First let use find for the value of constant k. We know
that the formula for half-life is:
t-half life = ln 2 / k
Finding for k:
5730 = ln 2 / k
k = 1.21 * 10^-4 yr^-1
Since it is stated that A = 0.00061 Ao, therefore
substituting all the values into equation 1:
0.00061 Ao / Ao = e^(-1.21 * 10^-4 yr^-1 * t)
Finding for t:
t = 61,173.98 years
<span>The person died about 61,174 years ago.</span>
A function is a type of relation in which there is only one output value for each input value so the domain will not repeat if it is going to be a continuous graph remember there will be no dots just curves and 00 origin
The answer: is 8
Explanation:
12 - 4n = 20 4 x 8 = 32
32 - 12 = 20 ur welcome:)
Answer:
h(4) = -1 ; h(-5) = 1 h(0) = -9
Step-by-step explanation:
a) h(x) = |-2x| - 9 Substitute x = 4
h(4) = | -2 · 4| - 9
h(x) = | -8| - 9
h(4) = 8 - 9
h(4) = -1
b) h(x) = |-2x| - 9 Substitute x = -5
h(-5) = |-2 · -5| - 9
h(-5) = |-10| - 9
h(-5) = 10 - 9
h(-5) = 1
c) h(x) = |-2x| - 9 Substitute x = 0
h(0) = |-2 · 0| - 9
h(0) = |0| - 9
h(0) = 0 - 9
h(0) = -9