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Y_Kistochka [10]

4 years ago

8

Identify and explain the three different ways that charge is built up on an object.

1 answer:

8090 [49]4 years ago

8 0

Answer:

There are three ways to charge an object: friction, conduction and induction. Friction involves rubbing on material with another, resulting in electrons moving from one surface to another. ... Friction is useful for charging insulators, which are materials that aren't good conductors.

Explanation:

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An image formed by a concave lens is <br> virtual/real

sergejj [24]

A concave<span> mirror and a converging </span>lens<span> will only produce a </span><span>real image</span>

6 0

4 years ago

April and Alex are saving money to buy new phones. Each friend starts with some money and saves a specific amount each week.

qwelly [4]

First thing to note is that we are on week 0, when they start saving:

The equation for Alex is:

y=20x + 125

Know that we are on week 0, and x is our weeks, that makes our equation:

y=20(0) + 125

Which means it's really:

y=125

That means that the first one is E. 125

For the second, it shows our week 0, which is at 100.

That means that the second one is I. 100

Hope this helps!

5 0

4 years ago

Read 2 more answers

The current in a wire is 4.00A. How much time is needed for 1 mole of electrons (6.02×1023 electrons) to pass a point in the wir

scZoUnD [109]

Answer:

t= 24080 s

Explanation:

Given that

Current in the wire ,I = 4 A

The charge ,q = 6.02 x 10²³ e C

We know that

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

$t=\dfrac{q}{I}$

Now by putting the values in the above equation we get'

$t=\dfrac{6.02\times 10^{23}\times 1.6\times 10^{-19}}{4}\ s$

t= 24080 s

8 0

3 years ago

A 0.0140 kg bullet traveling at 205 m/s east hits a motionless 1.80 kg block and bounces off it, retracing its original path wit

makvit [3.9K]

Answer:

Final velocity of the block = 2.40 m/s east.

Explanation:

Here momentum is conserved.

Initial momentum = Final momentum

Mass of bullet = 0.0140 kg

Consider east as positive.

Initial velocity of bullet = 205 m/s

Mass of Block = 1.8 kg

Initial velocity of block = 0 m/s

Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s

Final velocity of bullet = -103 m/s

We need to find final velocity of the block( u )

Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u

We have

2.87 = -1.442 + 1.8 u

u = 2.40 m/s

Final velocity of the block = 2.40 m/s east.

7 0

4 years ago

You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Y

Dvinal [7]

Answer:

$380697.33\ \text{N/m}$

$0.138\ \text{m}$

Explanation:

m = Mass rocket = 1070 kg

v = Velocity of rocket = 3.75 m/s

a = Acceleration of rocket = 5g

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

The energy balance of the system is given by

$\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}$

The force balance of the system is given by

$ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}$

The distance the spring must be compressed is $0.138\ \text{m}$

$k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}$

The force constant of the spring is $380697.33\ \text{N/m}$ .

4 0

3 years ago