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sveta [45]
3 years ago
13

Projectile effects are a hazard in __________________. magnetic resonance imaging (MRI) fields pediatric units emesis stations o

perating theaters
Physics
1 answer:
zhenek [66]3 years ago
3 0

Projectile effects are a hazard in MRI fields.

<h3>What is MRI field?</h3>

MRI stands for - Magnetic resonance imaging and it is a medical imaging technique that uses a magnetic field and radio waves to create detailed images of the organs and tissues in your body.

Projectile effects are a hazard in MRI fields, due to attraction exerted by the static magnetic field of the MRI scanner on ferromagnetic objects accidentally introduced into the MRI-scanner room.

Thus, Projectile effects are a hazard in MRI fields.

Learn more about MRI fields here:  brainly.com/question/23730902

#SPJ1

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DESCRIBE THE FORMATION OF THE SOLAR SYSTEM ACCORDING TO THE NEBULAR THEORY
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3 years ago
How do we get this equation ??<br><br><br> H=V^2÷R
lesantik [10]

H=\frac{V^2}{R}\times t is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to  

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = H = I^2 Rt .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

V\ \alpha\ I\\V=I\times R ...............................................(2)

From (2), Current (I) can be rewritten as

I = \frac{V}{R} ........................................................(3)

Substituting (3) in (1), we get

H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t

3 0
3 years ago
For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas
nirvana33 [79]

Explanation:

The force of the roller-coaster track on the cart at the bottom is given by :

F=\dfrac{mv^2}{R}, m is mass of roller coaster

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R = 60 m v = 16 m/s

F=\dfrac{(16)^2m}{60}=4.26m\ N

Case 2.

R = 15 m v = 8 m/s

F=\dfrac{(8)^2m}{15}=4.26m\ N

Case 3.

R = 30 m v = 4 m/s

F=\dfrac{(4)^2m}{30}=0.54m\ N

Case 4.

R = 45 m v = 4 m/s

F=\dfrac{(4)^2m}{45}=0.36m\ N

Case 5.

R = 30 m v = 16 m/s

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Case 6.

R = 15 m v =12 m/s

F=\dfrac{(12)^2m}{15}=9.6m\ N

Ranking from largest to smallest is given by :

F>E>A=B>C>D

5 0
3 years ago
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