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givi [52]
3 years ago
13

11

Physics
1 answer:
Virty [35]3 years ago
6 0

Answer:

it is missing some numbers

Explanation:

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What is the net force on this object?
vaieri [72.5K]

Answer:

200 newtons

Explanation:

because the sub air that would pull the force down by all of the mass of the sub air go down by that 400 newtons there for your anwer is 200 newtons. because 600-400=200

8 0
3 years ago
Read 2 more answers
16 grams of ice at –32°C is to be changed to steam at 182°C. The entire process requires _____ cal. Round your answer to the nea
ICE Princess25 [194]

Answer:

12432 cal.

Explanation:

The process to change ice at -32 ºC to steam at 182 ºC can be divided into 5 steps:

1. Heat the ice to 0 ºC, which is the fusion temperature.

2. Melt the ice (obtaining liquid water), which is a process at constant pressure and temperature, so the liquid obtained is also at 0ºC.

3. Heat the liquid water from 0 ºC to 100 ºC, which is the vaporization normal temperature of the water.

4. Vaporization of all the water; this is also a process that occurs at constant pressure and temperature, so the produced steam will be at 100ºC.

5. Heat the steam from 100 ºC to 182 ºC.

Each process has a required energy, and the sum of the energy required for each and all of the steps is the total amount of energy required for the whole process:

E_T=E_1+E_2+E_3+E_4+E_5

E_1 is a heating process for the ice, so we know that the energy required is proportional to the temperature difference through the specific heat:

E_1=m*Cp_{sol}*(T_2-T_1)\\E_1=16g*0.5\frac{cal}{gC}*(0-(-32))=256cal

E_2 is a phase change process, so we do not use the specific heat (sensible heat), but the fusion heat (latent heat), so:

E_{2}=m*dh_{f}={16g*80\frac{cal}{g}}=1280cal

Analogously,

E_3=m*Cp_{liq}*(T_3-T_2)=16g*1.00\frac{cal}{gC}*(100-0)C = 1600 cal

E_{4}=m*{dh_{vap}}\\\\E_4=16g*540\frac{cal}{g} =8640cal

E_{5}=m*Cp_{vap}*(T_{5}-T_{4})\\E_{5}={16g*0.5\frac{cal}{gK}*(182-100)K}=656cal

Finally, the total energy required is:

E_T=256cal+1280cal+1600cal+8640cal+656cal\\E_T=12432cal

8 0
3 years ago
Can i have the physical science grade 12 june 2021 paper (common paper)​
Veseljchak [2.6K]

Answer:

u have to purchase it via online e-commerce platforms

7 0
3 years ago
Read 2 more answers
A whistle of frequency 564 Hz moves in a circle of radius 71.2 cm at an angular speed of 17.1 rad/s. What are (a) the lowest and
trapecia [35]

Answer:

a) f'=544.66 \textup{Hz}

b) f'=584.75 \textup{Hz}

Explanation:

Given:

Frequency of the whistle, f = 564 Hz

Radius of the circle, r = 71.2 cm = 0.712 m

Angular speed, ω = 17.1 rad/s

speed of source, v_s = rω = 0.712 × 17.1 = 12.1752 m/s

speed of sound, v = 343 m/s

Now, applying the Doppler's effect formula, we have

f'=f\frac{v\pm v_d}{v\pm v_s}

where,

v_d = relative speed of the detector with respect to medium = 0

a) for lowest frequency, we have the formula as:

f'=f\frac{v}{v+v_s}

on substituting the values, we get

f'=564\times\frac{343}{343+12.1752}

or

f'=544.66 \textup{Hz}

b) for maximum frequency, we have the formula as:

f'=f\frac{v}{v-v_s}

on substituting the values, we get

f'=564\times\frac{343}{343-12.1752}

or

f'=584.75 \textup{Hz}

3 0
3 years ago
During a workout, a football player pushes a blocking dummy a distance of 30 m. While pushing the dummy the same distance a seco
Pavel [41]

Explanation:

Power = work / time

Work = force × distance

Therefore:

Power = force × distance / time

Since the distance is the same, he would have to either increase the force he exerts or decrease the time (increase his velocity) in order to increase the amount of work done.

5 0
3 years ago
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