1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
adoni [48]
3 years ago
9

What percent of 940 is 14.1

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

6666.66 (repeating)

Step-by-step explanation:

To solve, first note that 14.1 is 14.1%

Change the percent to a decimal. To do so, move the decimal point to the left two place values: 14.1% = 0.141

Divide: 940/0.141 =

940/0.141 = 666.66 (repeating 6)

6666.66 (repeating) is your answer

~

marusya05 [52]3 years ago
6 0

Answer:

o get the solution, we are looking for, we need to point out what we know.  

1. We assume, that the number 14.1 is 100% - because it's the output value of the task.  

2. We assume, that x is the value we are looking for.  

3. If 100% equals 14.1, so we can write it down as 100%=14.1.  

4. We know, that x% equals 940 of the output value, so we can write it down as x%=940.  

5. Now we have two simple equations:

1) 100%=14.1

2) x%=940

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=14.1/940

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 940 is what percent of 14.1

100%/x%=14.1/940

(100/x)*x=(14.1/940)*x       - we multiply both sides of the equation by x

100=0.015*x       - we divide both sides of the equation by (0.015) to get x

100/0.015=x  

6666.6666666667=x  

x=6666.6666666667

now we have:  

940 is 6666.6666666667% of 14.1


You might be interested in
SOMBODY PLZ HELP!!!! I WILL GIVE BRAINLIST
trapecia [35]
P is dependent and 2b is independent
7 0
3 years ago
A hiker maintains an average speed of 3 3/4 km/h. How many kilometers will the hiker walk in 5 hours
dalvyx [7]

Answer:

3 3/4 km = 1 hr

_______. ____

x 5

5 (3 3/4) = 18.75 km

5 0
2 years ago
Read 2 more answers
Help, please! If possible explain it like your talking to a little kid :) Thank you♡
monitta

Answer:

GCF: y³z³

Step-by-step explanation:

The greatest common factor is the a term that you can take out of all the terms given to you. This term, when multiplied to each of the individual numbers in the set, will return you to the original amount.

In this case, note that they all share the variables y and z, and that each of them have <em>at least</em> 3 y's and 3 z's. For you to factor, you will divide these from all the terms.

\frac{x^{3}y^{5}z^{5} , y^{3}z^{5} , xy^{3}z^{3} }{y^{3}z^{3}} = x^{3}y^{2}z^{2} , z^{2} , x

y³z³(x³y²z² , z² , x)

~

7 0
3 years ago
NO LINKS!!! Please help find the match​
Mkey [24]

Answer:

HI = 8

TU = 45

Step-by-step explanation:

→ Find the scale factor enlargement

45 ÷ 10 = 4.5

→ Multiply JI by the scale factor to find it

10 × 4.5 = 45

→ Divide UV by the scale factor to find it

36 ÷ 4.5 = 8

3 0
2 years ago
Read 2 more answers
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Other questions:
  • probability distribution that meets these requirements: 1) the procedure has a fixed number of trials; 2) the trial must be inde
    10·1 answer
  • A plane takes off at an angle of 15 and travels in a straight line for 3000 meters what's the height
    15·1 answer
  • QUICK HELP ME !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    12·2 answers
  • Help me with my math problems
    8·1 answer
  • Please answer correctly !!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!
    14·1 answer
  • A box is filled with 9 red crayons, 5 blue crayons, and 8 yellow crayons.
    13·2 answers
  • Is time a function of distance?
    11·1 answer
  • <img src="https://tex.z-dn.net/?f=%5Csqrt%7B-63%5C%5C" id="TexFormula1" title="\sqrt{-63\\" alt="\sqrt{-63\\" align="absmiddle"
    14·1 answer
  • 7.
    6·1 answer
  • On Monday Jill ought 3 teas and 5 coffees for £10.50 On Tuesday she bought 4 teas and 4 coffees for £10 On Wednesday she bought
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!