Question

Syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To what temperature must the gas in the syringe be heated/cooled in order to have a volume of 435 mL at 2.50 atm

Answer 1

Answer:

720.535 K

Explanation:

Concept tested: Combined gas law

From the question we are given;

• Initial volume, V1 of the gas is 285 mL
• Initial pressure, P1 of the gas is 1.88 atm
• Initial temperature, T1 of gas is 355 K
• Final pressure of the gas, P2 = 2.50 atm
• Final volume of the gas, V2 = 435 mL                                                      

We are required to calculate the new temperature, T2of the gas;

• To solve the question we are going to use the combined gas law.
• According to the combined gas law;

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

• Rearranging the formula we can calculate the new temperature;

$T2=\frac{P2V2T1}{P1V1}$

• Therefore;

$T2=\frac{(2.50atm)(435mL)(355K)}{(1.88atm)(285mL)}$

$T2=720.535K$

Therefore, the new temperature of the gas in the syringe must be 720.535 K