Answer:
%H = 6.72 %
Explanation:
Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.
So,
Percent composition of Hydrogen will be given as,
%H = Total mass of H / Molecular Mass of Acetic Acid × 100
So,
Total Mass of H = 1.01 × 4 = 4.04 g
Molecular Mass of Acetic acid = 60.052 g/mol
Putting values in above formula,
%H = 4.04 g/mol ÷ 60.052 g/mol × 100
%H = 6.72 %
In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.
So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Learn more about number of moles here:
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