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attashe74 [19]
4 years ago
11

Four students all do the same experiment for the science fair. They test reaction times for pushing a button when a specific col

or is shown. Their data is as follows:
⎡⎣⎢⎢⎢⎢⎢⎢⎢⎢Student 1Student 2Student 3Student 4Reaction Time (seconds)Trial 10.440.350.410.42Trial 20.410.430.520.43Trial 30.470.380.570.41Trial 40.390.390.460.42Trial 50.460.420.550.41Trial 60.420.440.490.42⎤⎦⎥⎥⎥⎥⎥⎥⎥⎥
[
Reaction Time(seconds) Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Trial 6 Student 1 0.44 0.41 0.47 0.39 0.46 0.42 Student 2 0.35 0.43 0.38 0.39 0.42 0.44 Student 3 0.41 0.52 0.57 0.46 0.55 0.49 Student 4 0.42 0.43 0.41 0.42 0.41 0.42
]



Put the students in order from most to least reliable data.

A. Student 1, Student 2, Student 3, Student 4
B. Student 4, Student 1, Student 2, Student 3
C. Student 2, Student 1, Student 4, Student 3
D. Student 3, Student 2, Student 1, Student 4
Chemistry
1 answer:
emmasim [6.3K]4 years ago
3 0
Sorry, Cant really tell how to differentiate the students and trial times
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If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

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2 years ago
5) Read each Eco fact. Propose a solution to prevent the environmental problems of the
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Answer:

The creation of regulations that limit timber activities and the exploitation of wood can prevent soil erosion in Troy.

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The exploitation of the wood was an intense activity and that did not have any regulation that would limit its damages, caused by its exploratory activities.

As the timber market was totally undisciplined, the exploitation of the wood caused a strong deforestation, leaving the soil totally unprotected and susceptible to strong erosion.

Soil erosion has a very negative impact on the environment, requiring regulations to be made to prevent this from happening.

Based on this, we can say that one way to prevent environmental problems in the seaport of troy is by establishing laws and regulations that limit logging activities.

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3 years ago
Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
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Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

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Now, the values of K_b is calculated as follows.

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K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

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How many atoms are there in 2.0 moles of magnesium (Mg)?
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It should be 1. 1.2 X 10^24

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