No of atoms in 4.8 dm³ of neon gas is determined in the following way.
Explanation:
We have given
Neon Gas=4.8dm³
At STP
1 mole of an ideal gas occupies 22.4 L(dm³) of volume.
which means that number of molecules occupy 22.4 L of volume.
So
4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon
0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon
No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon
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Answer : The original concentration of copper (II) sulfate in the sample is, 
Explanation :
Molar mass of Cu = 63.5 g/mol
First we have to calculate the number of moles of Cu.
Number of moles of Cu = 
Now we have to calculate the number of moles of 
Number of moles of Cu = Number of moles of
Number of moles of = 
Now we have to calculate the molarity of
Now put all the given values in this formula, we get:
To change mol/L into g/L, we need to multiply it with molar mass of
Molar mass of = 159.609 g/mL
Concentration in g/L = 
Thus, the original concentration of copper (II) sulfate in the sample is,
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If you count the number of electrons (small dots), you have the atomic number. In this case you have 11 so this atom is a sodium atom. Sodium has 1 valence electron (electron on the outer shell) and chlorine has 7. This means that if sodium gave one electron away and chlorine would obtain one electron, they would both have the (ideal) noble gas conformation (full outer shell).
