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Black_prince [1.1K]

3 years ago

9

Please help me so I can pass this class

1 answer:

djyliett [7]3 years ago

6 0

Answer:

(B)

Explanation:

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Write the 1 g equivalents using the following prefixes: (a) mega−, (b) kilo−, (c) deci−, (d) centi−, (e) milli−, (f) micro−, (g)

dem82 [27]

<u>Explanation:</u>

Unit is defined as the quantity that is used as a standard for measurement.

S.I. unit of mass of kilograms. Other units in which mass of a substance can be measured are grams, milligrams, etc...

All these units are inter convertible.

<u>For a:</u> Mega-

The conversion factor used is:

$1g=10^{-6}Mg$

<u>For b:</u> kilo-

The conversion factor used is:

$1g=10^{-3}kg$

<u>For c:</u> deci-

The conversion factor used is:

$1g=10dg$

<u>For d:</u> centi-

The conversion factor used is:

$1g=10^{3}cg$

<u>For e:</u> milli-

The conversion factor used is:

$1g=10^3mg$

<u>For f:</u> micro-

The conversion factor used is:

$1g=10^6\mu g$

<u>For g:</u> nano-

The conversion factor used is:

$1g=10^9ng$

<u>For h:</u> pico-

The conversion factor used is:

$1g=10^{12}pg$

8 0

3 years ago

How are the periods, or horizontal rows, on a periodic table ordered from left to right? (2 points)

Anarel [89]

#2
They are ordered by increasing number of protons (aka atomic number)

6 0

4 years ago

Read 2 more answers

Answer all with detail please! Easy for those who have completed chemistry courses!

Zina [86]

a) CH2O

each element can be divided by 2

b) BCl3

the molecule is already in it's empirical formula

c) CH4

the molecule is already in it's empirical formula

d)CH2O

each element can be divided by 6

5 0

3 years ago

Question in pic! Thank u so much in advance for responding

romanna [79]

If Cf collides with an alpha particle, this particle will be in the reactants side on the equation.

So reactants side:

$^{242}_{98}Cf+^4_{2^{}}\alpha^{}$

It will produce 242+4-1 = 245

And 98 + 2 = 100

So products side will be:

$^{245_{}}_{100}Fm+^1_0\text{n}$

Answer:

$^{245}_{100}Fm$

6 0

1 year ago

Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam

Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

$IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O$

$I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}$

$C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+$

Looking at the above reactions

The original number of moles of $I^{3-}$ = 3 × number of moles of $IO^{3-}$

= 3 × volume × concentration of $KIO_3$

Note: The formula for number of moles is volume × concentration

$=3 * \frac{40}{1000} * 0.00653 =0.000784$ mol

The number of moles of $I^{3-}$ left after its reaction with ascorbic acid

= $\frac{1}{2}$ x moles of $S_2O_3^{2-}$

= $\frac{1}{2}$ x volume x concentration of $S_2O_3^{2-}$

$= \frac{1}{2} * \frac{15}{1000} * 0.0510 =0.000383 \ mol$

Note: The division by 1000 is to convert mill liter to liter

Moles of ascorbic acid = moles of $I^{3-}$ reacted

$= initial \ moles \ of \ I^{3-} \ - remaining \ moles \ of \ I^{3-}$

$=0.000784 - 0.000383$

$=0.000401 \ mols$

$Mass = moles \ * molar \ mass$

Hence

Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

$= 0.000401* 176.12 = 0.07055\ g$

$= 70.55\ mg$

Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

= 70.55/80 × 100%

= 88.1%

3 0

4 years ago