2 dice are rolled. What is the probability that the sum of the numbers rolled is a number greater than or eaqual to 5
2 answers:
Answer:1/3
Step-by-step explanation:
So first we need our denominator. Which we can get by adding all the possibilities so there are 6 sides on each dice. 6+6=12 So there is our bottom half. There are two 5's and two 6's so that's four. So we have 4 as a numerator . Let's put them together now 4/12. Now we can reduce this to 2/6. We can reduce it again to 1/3 and that would be your answer.
2 + 3 = 5 > = 5; 2 + 4 = 6 > =5; 2 + 5 = 7 >= 5; 2 + 6 = 8 >= 5; 3+2 = 5 >= 5; 3 + 3 = 6 >= 5; 3 + 4 = 7 >= 5; 3 + 5 = 8 >= 5; 3 + 6 = 9 >= 5; 4+1 = 5 >= 5; 4+2 = 6 >= 5; 4+3 = 7 >= 5; 4+4 = 8 >= 5; 4+5 = 9 >= 5; 4+6 = 10 >= 5; 5+1 = 6 >= 5; 5+2 = 7 >= 5; .............. 6 + 6 = 12 >= 5; Number of ways it can happen = 27; Total number of outcomes = 6*6 = 36; Probability of an event happening = Number of ways it can happen<span><span> / </span>Total number of outcomes => Probability = 27/36 = 0.75;</span>
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