First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.

Volume formula of Sphere

V = $\frac{4}{3} \pi r^2$

Substitute 1 in for r

$\frac{4}{3} \pi (1)^2 = \frac{4}{3} \pi = 4.189$ = Volume

Finding the Height of a Cone

Volume formula for Cone: $V = \pi r^2\frac{h}{3}$

Solve for h

Multiply both sides by 3, then divide by pi and r^2.

$h = \frac{3V}{\pi r^2}$

Plug in the volume and the radius.

$h = \frac{3(4.189)}{\pi (1)^2}$

Simplify

$h = \frac{12.567}{\pi }$

h ≈ 4

4 is approximately the height.

#TeamTrees #PAW (Plant And Water)

6 0

3 years ago

given a polynomial and one of its factors, find the remaining factors of the polynomial. some factors may not be binomials. use

Alenkinab [10]

This is easy to do because you can factor
example
6/2=3 because 6=2*3 so 6/2=3/1 times 2/2 or 3

2x^3+17x^2+23x-42 can be factored out to equal
(x-1)(x+6)(2x+7)

so [(x-1)(x+6)(2x+7)]/(2x+7)=[(x-1)(x+6)] times (2x+7)/(2x+7)=(x-1)(x+6)=x^2+5x-6

the answer is (x-1)(x+6) or x^2+5x-6

3 0

4 years ago

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You draw 4 cards from a deck of 52 cards with replacement. What are the probabilities of drawing a black card on each of your fo

lawyer [7]

Solution:

As, in a pack of cards, there are 26 black cards and 26 red cards.

Probability of an event = $\frac{\text{total favorable outcome}}{\text{total possible outcome}}$

Probability of drawing a black card from a pack of 52 cards = $\frac{26}{52}=\frac{1}{2}$

As each card drawn is replaced,Each black card draw is an independent with another black card draw.

Probabilities of drawing a black card on each of four trial=

$\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=[\frac{1}{2}]^4$

4 0

3 years ago

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