<u>Unit rate 4:</u>
The table
d n
4 1
8 2
16 4
<u>Unit rate 1/4:</u>
Table
d n
1 4
4 16
16 64
and
The equation n=4d
<u>Unit rate 16:</u>
Equation:
d = 16n
Step-by-step explanation:
The unit in the unit rate is dollars per unit ounces which means that the unit rate calculated by

So,
The first option is the equation:

The unit rate is 16 dollars per ounce
The second option is the table:
d n
1 4
4 16
16 64
We can take any pair of values of d and n from the table to calculate the unit rate
So taking
d = 1
n=4

The unit rate for table is: 1/4 dollars per ounces
Third option is the equation:
n = 4d

dividing both sides by n

dividing both sides by 4

the unit rate is 1/4 dollars per ounce
Fourth option is the table:
d n
4 1
8 2
16 4
We will take any pair of d and n to find the unit rate
So,
Taking
d = 4
n =1

The unit rate is 4 dollars per unit ounce.
Keywords: Unit rate, units
Learn more about unit rate at:
#LearnwithBrainly
Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2
X is 10 take that’s known 80 degrees and the fact that it is a right angle means the whole this is 90 degrees so therefore x is 10 90=80+_
In this question, we're calculating how much you're going to need to pay in parking.
We know that it costs 50¢ per hour
We also know that you park for 7 hours.
Note: They're trying to trick you here with the $4 per day, you wouldn't use this information because you're not parking for the whole day.
Calculate how much you're paying per day by multiplying 7 by 0.50
7 × 0.50 = 3.5
Now, multiply how much you pay everyday (3.5) by the amount of days your'e working (5)
3.5 × 5 = 17.50
This means that you will be paying $17.50 for 5 days of parking
Answer:
$17.50