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4 years ago

10

Bart stole a watermelon in ran 5,000 feet from the cops to chase lasted 0.1 hours how fast was Bart running in miles per hour...

.. And please show me your work

1 answer:

valentinak56 [21]4 years ago

3 0

5000 feet = 0.947 miles.

Speed= ?
Distance=o.947 miles
Time= 0.1 hours

Speed=distance/time
= 0.947/0.1
=9.47 miles per hour

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Disabling asthma attacks can lead to restrictive school activity of approximately

mamaluj [8]

Answer:

<h2>Yes.</h2>

Explanation:

If we want to "disable" astham attacks, that would imply too many restictions for those people who can suffer from these attacks. For example, in order to avoid these attacks, they couldn't do sport activities, because that would alter their respiratory system, which occasionate astham attacks.

Therefore, this statement is true.

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3 years ago

Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about the amounts o

likoan [24]

Answer:

1) At the highest point of the building.

2) The same amount of energy.

3) The kinetic energy is the greatest.

4) Potential energy = 784.8[J]

5) True

Explanation:

Question 1

The moment when it has more potential energy is when the ball is at the highest point in the building, that is when the ball is at a height of 40 meters from the ground. It is taken as a point of reference of potential energy, the level of the soil, at this point of reference the potential energy is zero.

$E_{p} = m*g*h\\E_{p} = 2*9.81*40\\E_{p} = 784.8[J]$

Question 2)

The potential energy as the ball falls becomes kinetic energy, in order to be able to check this question we can calculate both energies with the input data.

$E_{p}=m*g*h\\ E_{p} = 2*9.81*20\\ E_{p} = 392.4[J]\\$

And the kinetic energy will be:

$E_{k}=0.5*m*v^{2}\\ where:\\v = velocity = 19.8[m/s]\\E_{k}=0.5*2*(19.8)^{2}\\ E_{k}=392.04[J]$

Therefore it is the ball has the same potential energy and kinetic energy as it is half way through its fall.

Question 3)

As the ball drops all potential energy is transformed into kinetic energy, therefore being close to the ground, the ball will have its maximum kinetic energy.

$E_{k}=E_{p}=m*g*h = 2*9.81*40\\ E_{k} = 784.8[J]\\ E_{k} = 0.5*2*(28)^{2}\\ E_{k} = 784 [J]$

Question 4)

It can be easily calculated using the following equation

$E_{p} =m*g*h\\E_{p}=2*9.81*40\\E_{p} =784.8[J]$

Question 5)

True

The potential energy at 20[m] is:

$E_{p}=2*9.81*20\\ E_{p}= 392.4[J]\\The kinetic energy is:\\E_{k}=0.5*2*(19.8)^{2} \\E_{k}=392[J]$

3 0

3 years ago

You are standing 10 meters from a light source. Then, you back away from the light source until you are 20 meters away from it.

aliya0001 [1]

From my new perspective, the new intensity of the
light source has decreased by a factor of four.

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3 years ago

Read 2 more answers

Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope

mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

Em₀ = U = m g y

Lowest point

$Em_{f}$ = K = ½ m v²

As there is no friction, mechanical energy is conserved

Em₀ = $Em_{f}$

m g y = ½ m v²

v = √ 2 g y

Where we can use trigonometry to find and

sin 30 = y / L

y = L sin 30

Let's replace

v = RA (2 g L sin 30)

Let's calculate

v = RA (2 9.8 100.0 sin30)

v = 31.3 m / s

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3 years ago

A 70-kg astronaut (including spacesuit and equipment) is floating at rest a distance of 13 m from the spaceship when she runs ou

Keith_Richards [23]

Answer:

Explanation:

mass of the astronaut including the spacesuit, $M=30$

distance of astronaut from the spaceship, d = 13 m

mass of the oxygen tank, m = 3 kg

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a)

<u>Using the conservation of linear momentum:</u>

total momentum before collision = total momentum after collision

$M.u=m.v+(M-m)v'$

$0=3\times 15+(70-15)\times v'$

$v'=0.82~m/s$

b)

She mush hold her breath until she reaches the spaceship, i.e.

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$t=13/0.82$

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3 years ago