All categories

2 years ago

3. A man hits a 0.2 kg golf ball with a force of 4

Physics

1 answer:

pogonyaev2 years ago

8 0

Answer:

Force(f)= mass x acceleration

Acceleration (a) is the rate of change in velocity.

F=4N

M=0.2kg

a=F/M

a=4/0.2

a=20m/s^2

Explanation:

You might be interested in

A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 206

vampirchik [111]

Power = (voltage) x (current). The motor consumes (12)x(206)=2,472 watts. Some of it is dissipated as heat, but most of it is used to do useful work by turning the engine over to make it start.

5 0

3 years ago

Which statement best describes a wave?

dedylja [7]

Correct answer choice is:

D. A continuous transmission of energy from one location to the next.

Explanation:

Waves include the carrier of energy without the carrier of matter. In outcome, a wave can be characterized as a change that progresses into a medium, carrying energy from one spot (its source) to different spot without carrying matter.

3 0

2 years ago

Read 2 more answers

A rock with a mass of 540 g in air is found to have an apparent mass of 342 g when submerged in water. (a) What mass of water is

AleksandrR [38]

(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

- its weight, equal to $W=mg$ (m=mass, g=acceleration of gravity), downward

- the buoyant force, equal to $B=m_w g$ ( $m_w$ =mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

$W'=W-B$

which can be rewritten as

$m'g = mg-m_w g$

where m' is the apparent mass of the rock. Using:

m = 540 g

m' = 342 g

we find the mass of water displaced

$m_w = m-m'=540 g-342 g=198 g$

(b) $1.98\cdot 10^{-4} m^3$

If the rock is completely submerged, the volume of the rock corresponds to the volume of water displaced.

The volume of water displaced is given by

$V_w = \frac{m_w}{\rho_w}$

where

$m_w = 198 g = 0.198 kg$ is the mass of the water displaced

$\rho_w = 1000 kg/m^3$ is the density of the water

Substituting,

$V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3$

And so this is also the volume of the rock.

(c) $2727 kg/m^3$

The average density of the rock is given by

$\rho = \frac{m}{V}$

where

m = 540 g = 0.540 kg is the mass of the rock

$V=1.98\cdot 10^{-4} m^3$ is its volume

Substituting into the equation, we find

$\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3$

3 0

3 years ago

What is Initial temperature and final temperature equations?? ...?

Neporo4naja [7]

One that can help you is:
ΔT=TFinal−TInitial
That is of course adding both tmepratures. There is one more that is a lil bit more complex
Tf=Ti−ΔHrxn∗nrxn/(Cp,water∗mwater)
This one is taking into account that yu can find temperature and that there could be a change with a chemical reaction. Hope this helps

8 0

3 years ago

Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu

ASHA 777 [7]

Answer:

the best way to prevent cancer is to eat right

Explanation:

4 0

3 years ago